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the answer is 200 Btu.

the formula is

weight x specific heat x temperature difference

so we have

10 pounds x 1.00 x 20

10 for 10 pounds of water

the specific heat of water is 1.00

and the temperature difference would be 70-50= 20

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How many btus will it take to raise 50 pounds of ice at 32 degrees to water at 160 degrees?

To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.


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To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.


How much does a gallon of water weight at 229 degrees?

The weight of a gallon of water at 229 degrees Fahrenheit would be approximately 8.33 pounds. This is because water's density changes with temperature, and at 229 degrees Fahrenheit, water is less dense compared to when it is at room temperature.


How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?

The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.


What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?

The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

Related Questions

How many btus will it take to raise 50 pounds of ice at 32 degrees to water at 160 degrees?

To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.


How many btus are required to raise the temperature of 15 pounds of water from 100 degrees fahrenheit to 130 degrees fahrenheit?

To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.


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1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.


) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?

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How much does a gallon of water weight at 229 degrees?

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How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?

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How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

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What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?

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How many BTUs are required to raise the temperature of 15 pounds of water from 100F to 120F?

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