The acceleration it would have if it were dropped and fell freely = g = 9.8m/s^2
F = ma
F= (1kg)(9.8m/s^2) = 9.8N
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force
Acceleration is directly proportional to applied force. When acceleration increases, force also increases. If the force is tripled, the acceleration will also be tripled. Note that the mass must remain constant...
Where the question says "2.8 g", we understand that to mean2.8 times the acceleration of gravity = 27.44 m/sec2 .F = M A = (1.2 kg) x (27.44 m/s2) = 32.928 newtons
Not necessarily. In our atmosphere, of course, we have friction due to the object displacing air, or if it is moving on some kind of wheel we have bearing friction, wheels (or what-have-you) against the road surface, etc. If the path or speed of the object is changing, then there is a force acting on it. Like the space station orbiting the Earth.
2.454731183m/s^2
Acceleration is in the same direction as the applied force.
F net=F applied - F friction
A wheel and axial eliminates energy expended in vertical displacement, you don't need to waste energy hold cargo up. A wheel and axial also eliminate (to a large degree) horizontal friction. Therefore most of the energy applied is used in horizontal acceleration.
Acceleration is 2m/s^2
Whenna given force is applied ,an oobject with greater mass will accelerate less
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force
The idea here is to multiply the force applied - the 300 N - by the distance over which it is applied. The force of friction does not affect the calculation. Note: Since the force of friction is less than the force applied, and if there are no other forces, the object will accelerate.
When a force is applied, mass and acceleration are inversely proportional. Newton's 2nd law, F=ma, says that if an equal force is applied to a larger mass, it will accelerate proportionally more slowly.
Acceleration is directly proportional to applied force. When acceleration increases, force also increases. If the force is tripled, the acceleration will also be tripled. Note that the mass must remain constant...
In general, when force is applied on any object it is accelerated in the direction of the applied force.The equation for the force is F = m*awhere m = massa = accelerationTo consider gravity, we can re-write the above equation as F = m*gwhere g = acceleration due to gravity (the gravitational constant) There may be an occasion where the applied force on an object is insufficient to break the existing dry friction, and the object will not move. In this case, the static and dynamic friction components "conspire" to hold the object in place. If the applied force exceeds the dry friction, the object will begin to accelerate, and the static friction will disappear. These are fundamental aspects of the laws of motion, and you can use the link below to learn more.
If the car and driver are moving (along a flat horizontal surface) at constant speed, then there is no acceleration, and the net horizontal force is zero.The applied 3,000N must be canceled by an effective total 3,000N of friction.
Where the question says "2.8 g", we understand that to mean2.8 times the acceleration of gravity = 27.44 m/sec2 .F = M A = (1.2 kg) x (27.44 m/s2) = 32.928 newtons