The kinetic energy of the SUV can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values, KE = 0.5 * 2000 kg * (31 m/s)^2 = 961,000 J. The SUV has 961,000 Joules of kinetic energy.
The kinetic energy of the car can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values gives: KE = 0.5 * 2000 kg * (25 m/s)^2 = 625,000 Joules. So, the kinetic energy of the car is 625,000 Joules.
It will be 8000 joules. ( if the velocity of a car has been doubled, the KE will be quadrupled. Because the KE is directly proportional to the velocity squared.)KE= 1/2 m v2
Given the car weighs 2000 kg and accelerates from rest to 20 m/s, the initial kinetic energy of the car is 0 J and the final kinetic energy is (1/2)mv^2 = (1/2) * 2000 * 20^2 = 400,000 J. However, since the engine is only 30% efficient, the actual kinetic energy provided by the engine is 400,000 J / 0.3 = 1,333,333.33 J.
The kinetic energy of the bus can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the bus and v is its velocity. Plugging in the values, KE = 0.5 * 2000 kg * (25 m/s)^2 = 625,000 Joules.
Initially energy of body will be: E=0.5mv^2 E=0.5*875*44^2 FInnally its energy will be: E=0.5*875*22^2 So loss in energy of body: E2-E1=0.5*875(44^2-22^2) SO this much energy is lost by the body if its speed is reduced to 22m/s. So we will have to do work equivalent to change energy to reduce its Energy. Work=E2-E1 Plz do the calculations
The kinetic energy of the car can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values gives: KE = 0.5 * 2000 kg * (25 m/s)^2 = 625,000 Joules. So, the kinetic energy of the car is 625,000 Joules.
It will be 8000 joules. ( if the velocity of a car has been doubled, the KE will be quadrupled. Because the KE is directly proportional to the velocity squared.)KE= 1/2 m v2
kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules
40,000 j
Assuming all have equal velocity the greater mass (20000g) will have the greater kinetic energy.
Given the car weighs 2000 kg and accelerates from rest to 20 m/s, the initial kinetic energy of the car is 0 J and the final kinetic energy is (1/2)mv^2 = (1/2) * 2000 * 20^2 = 400,000 J. However, since the engine is only 30% efficient, the actual kinetic energy provided by the engine is 400,000 J / 0.3 = 1,333,333.33 J.
The kinetic energy of the bus can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the bus and v is its velocity. Plugging in the values, KE = 0.5 * 2000 kg * (25 m/s)^2 = 625,000 Joules.
The answer will depend on the rate. 20 miles per day? per hour?
The formula for calculate the energy with in a moving object is :1/2mv.v solution:m=2000 kg v=70 m/h = 70 x 1609.3 m/hr = 112649 m/hr = 112649 / 3600 m/s = 31.3 ms-1 energy=1/2 x 2000 x 31.32 Js-1 = 979690 J = 979.69 kJ
kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules
Kinetic energy = (1/2) (mass) (speed)2KE = (1/2) (2,000) [ (50 km/hr) x (1,000 m/km) / (3,600 sec/hr) ]2= (1,000) (192.9) = 192,901.2 joules (rounded)
The Traveling Vampire Show was created in 2000-05.