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The work done by applying a force in the same direction of motion is force times distance. So in this case W = F x d = 250 x 15 = 3750 J. Power is work divided by time:

P = 3750 J / 10 s = 375 J/s

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Total energy is (1000 x 4) = 4,000 newton-meters = 4,000 joules

Power = energy/time = 4,000 joules/2 seconds = 2,000 joules per second = 2,000 watts.

250 w

Q: How much power is expended if you lift a 100 newton rock 5 meters in 2 seconds?

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Power = force x displacement / time taken So power = 50 x 3 / 3 = 50 W Power expended = 50 W

Power = Force x displacement/time = 500 x 1000 / 120 = 4166.67 W

The formula for power is: amount of work / time interval 200 J / 1 sec. The amount of power expended: 200 Watts

247 W

If you multiply the weight (mass x gravity) by the height, you get the energy required. (Note: gravity is about 9.8 newton / kilogram.) You then need to divide that by the time, to get the power.

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The power during the lift is (weight of the barbell in Newtons)/4.4 watts.Note:Power is not "expended". Energy is. Power is the rate at which energy is expended.

Power = (energy) / (time) = (35 x 5) / 19 = 175 newton-meters / 19 seconds = 9.2105 watts (rounded)

Power = (energy) / (time) =(200 newtons x 4 meters) / (4 seconds) =200 newton-meters per second = 200 watts

Power = force x displacement / time taken So power = 50 x 3 / 3 = 50 W Power expended = 50 W

Power = Force x displacement/time = 500 x 1000 / 120 = 4166.67 W

The formula for power is: amount of work / time interval 200 J / 1 sec. The amount of power expended: 200 Watts

247 W

First mulitiply Newton x meter to get the energy (or work) required. Then divide the result by the time to get the power.

Work = (800 newtons) x (10 meters) = 8,000 newton-meters = 8,000 joulesPower = (work) / (time) = (8,000) / (5) = 1,600 watts

Work = (force) x (distance) = 500 x 4 = 2,000 joules Power = Work/time = 2,000/3 = 6662/3 watts

Horse power, kw/h, kilowatts, ftlb, newton meters... any rating of power will suffice

200 newton-meters per second = 200 watts.