Power is the rate at which work is done. To find the power required to do 100 J of work in 5 s, divide the work by the time: 100 J / 5 s = 20 watts. If the same work is done in 1 s, the power required would be 100 watts, as power is inversely proportional to time.
Power is calculated as work done divided by time taken, so power = work/time. In this case, power = 110 J / 0.6 s = 183.33 watts.
The work done by the machine would be the force required to lift the object multiplied by the distance it was lifted, which is 500kg * 9.81 m/s^2 * 20m = 98100 J. The power output would then be work done divided by time taken, which is 98100 J / 60 s = 1635 W or 1.64 kW.
Power = (energy used) / (time to use that much energy) = 40/5 = 8 watts
300 W
To calculate the work done when lifting an object, you can use the formula: work = force × distance. The force required to lift an object is equal to its weight, which is mass × gravity. So, you would need to know the mass of the object to calculate the work done when lifting it 1600 meters.
Power is calculated as work done divided by time taken, so power = work/time. In this case, power = 110 J / 0.6 s = 183.33 watts.
The work done by the machine would be the force required to lift the object multiplied by the distance it was lifted, which is 500kg * 9.81 m/s^2 * 20m = 98100 J. The power output would then be work done divided by time taken, which is 98100 J / 60 s = 1635 W or 1.64 kW.
Power = (energy used) / (time to use that much energy) = 40/5 = 8 watts
300 W
The power required to move the bag of books can be calculated by dividing the work done (12900 J) by the time taken (3 minutes = 180 s). So, the power required is 71.67 watts.
To calculate the work done when lifting an object, you can use the formula: work = force × distance. The force required to lift an object is equal to its weight, which is mass × gravity. So, you would need to know the mass of the object to calculate the work done when lifting it 1600 meters.
To double an object's velocity in air, the power required increases by a factor of eight. This is because the kinetic energy of an object is proportional to the square of its velocity, so doubling the velocity means four times more power is needed. Additionally, factoring in air resistance, the actual power required may be higher due to the increased drag force at higher velocities.
The work done in lifting the crate is equal to its change in potential energy: ( \text{Work} = \text{Force} \times \text{distance} = m \cdot g \cdot h ). The power required is the work done divided by the time taken: ( \text{Power} = \frac{\text{Work}}{\text{time}} ). Plug in the values to calculate the power required.
The work done to lift the box is equal to the force applied multiplied by the distance moved, which is 20 joules in this case (10 N * 2 m). Power is the rate at which work is done, so if the box is lifted in 1 second, the power required would be 20 watts (20 joules / 1 second).
The work required to lift the object is given by the formula: work = force x distance. The force required to lift the object is equal to its weight, which is mass x acceleration due to gravity. Therefore, the work done would be the weight of the object x height it is lifted: W = (2.90 kg x 9.81 m/s^2) x 9.4 m = 262.38 Joules.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
To calculate the power required to lift the chair, we first find the work done, which is the product of force and distance. The work done is ( W = F \times d = 30.0 , \text{N} \times 0.20 , \text{m} = 6.0 , \text{J} ). Power is then calculated as work done over time, ( P = \frac{W}{t} = \frac{6.0 , \text{J}}{2.0 , \text{s}} = 3.0 , \text{W} ). Thus, the power required to lift the chair is 3.0 watts.