10 cm3 of water would displace an equivalent volume of water when submerged. This displacement would be equal to 10 ml or 10 grams of water.
The amount of water displaced by 500 grams of silver would be equal to the volume of the silver. To calculate this, you would need to divide the mass of the silver by the density of silver (which is 10.49 g/cm^3). This will give you the volume of the silver, which is equal to the volume of water displaced.
To find the density of an irregularly shaped object like a rock, you can use the water displacement method. First, measure the volume of water displaced when the rock is submerged in a known volume of water. Then, divide the mass of the rock by the volume of water displaced to calculate the density.
The buoyancy force acting on an object is equal to the weight of the water displaced by the object. If a boat displaces 600 kg of water, the buoyancy force will be equal to the weight of 600 kg of water (water density x volume of water displaced x gravity).
The buoyant force acting on a body in water is directly proportional to the volume of water displaced by the body. This is known as Archimedes' principle. The greater the volume of water displaced, the greater the buoyant force exerted on the body.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
Volume will determine how much water will be displaced. The volume of an object dictates how much space it occupies, which in turn determines the amount of water it displaces when submerged. Mass alone does not directly affect water displacement.
The amount of water displaced by 500 grams of silver would be equal to the volume of the silver. To calculate this, you would need to divide the mass of the silver by the density of silver (which is 10.49 g/cm^3). This will give you the volume of the silver, which is equal to the volume of water displaced.
The amount of water displaced is equal to the volume of the object submerged in the water. It can be calculated using the formula: volume of water displaced = weight of the object / density of water.
10ml's of water is equal to 10cm3 of water. 10cm3 of water has a mass of 10g. The specific heat of water is 4.134 J/K. The change in temperature is 1 degree Kelvin. Use Q=mC∆T which means Heat= (Mass)(Specific Heat)(Change in Temperature) Q= (10)(4.134)(1) Q=(10)(4.134) Q=41.34 Joules
The buoyant force acting on the boat is equal to the weight of the water displaced, which is equal to the weight of the boat. Therefore, a 10N boat would displace 10N of water.
measure the weight in grams and then put it in water and measure how much water is displaced. then divide milliliters displaced over grams and you have density.
Air is displace by water because water is much denser than air and therefor is much harder to compress.
An 800-pound boat would displace 800 pounds of water, according to Archimedes' principle. Since water has a density of approximately 62.4 pounds per cubic foot, the volume of water displaced can be calculated by dividing the weight by the density. This results in about 12.82 cubic feet of water displaced.
Use water and see how much is displaced (quickly)
1.8 is the answer to this question
the weight of the ship is equal to the amount of water displaced
First of all, if you're going to work with the volume of displaced water, it makes no difference at all how much water you start out with. The object would displace the same amount from a bucket as it would from Lake Michigan. But, to deal with the answer to your question: It's not possible to answer your question. The volume of water displaced is the same as the volume of the metal that you drop into the bucket. But you've only told us the area of one flat side of the metal. We have no idea what its volume may be until we also know its thickness.