That would be close to 26 gallons of water. Water weighs 8.3 pounds per gallon. If you freeze 8.3 pounds of water, it makes a bit more than 1 gallon, but 220 pounds of ice should come out to pretty close to 26 gallons of water.
To change one pound of ice at 20°F to steam at 220°F, you need to consider two processes: heating the ice to 32°F, melting the ice at 32°F, heating the water to 212°F, and finally boiling the water to steam at 220°F. The total number of BTUs required for this process is around 1440 BTUs.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
To change 10 lbs of ice at 20°F to steam at 220°F, you would need to consider the heat required for each phase change: Heating the ice from 20°F to 32°F (melting point) - specific heat of ice Melting the ice into water at 32°F - heat of fusion of ice Heating the water from 32°F to 212°F (boiling point) - specific heat of water Vaporizing the water into steam at 212°F - heat of vaporization of water Heating the steam from 212°F to 220°F - specific heat of steam
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
It depends on how much ice was in the glass and how much water it created as it melted. If the ice displaces enough water to raise the water level near the brim, then it could overflow once the ice melts and adds more water.
To change one pound of ice at 20°F to steam at 220°F, you need to consider two processes: heating the ice to 32°F, melting the ice at 32°F, heating the water to 212°F, and finally boiling the water to steam at 220°F. The total number of BTUs required for this process is around 1440 BTUs.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
To change 10 lbs of ice at 20°F to steam at 220°F, you would need to consider the heat required for each phase change: Heating the ice from 20°F to 32°F (melting point) - specific heat of ice Melting the ice into water at 32°F - heat of fusion of ice Heating the water from 32°F to 212°F (boiling point) - specific heat of water Vaporizing the water into steam at 212°F - heat of vaporization of water Heating the steam from 212°F to 220°F - specific heat of steam
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
220 grames
It depends how much water and how much ice you hae. if you have 1 ice cube and 6 cups of water, the water will weigh more. But, if you have 10 ice cubes and 1/4 cup of water the ice will weigh more.
Since ice is just frozen water it is actually good for you and you can't really eat too much water.
It depends on how much ice you have
Ice water is more dence then normal water because the particles in ice water move slower then normal water. This is because ice water has been in a much colder area then normal drinking water.
1 oz of water
70 % is water and 90% is ice
This depends on the type of water used to make ice.