0 J
(using squats for the sake of explanation) The lifter exerts an action force on the weight, which is in the opposite direction to gravity. The lifters shoulders also experience the reaction force (from the weight - otherwise, the weight would pass through the lifter or vice versa). The feet of the lift also experience a reaction force, which, combined with the shoulder-reaction force, is equal to the action force (Newton's Third Law). The feet also experience friction on the floor surface in opposite directions (which cancel out, so the lifter is stationary on the ground) :)
(using squats for the sake of explanation) The lifter exerts an action force on the weight, which is in the opposite direction to gravity. The lifters shoulders also experience the reaction force (from the weight - otherwise, the weight would pass through the lifter or vice versa). The feet of the lift also experience a reaction force, which, combined with the shoulder-reaction force, is equal to the action force (Newton's Third Law). The feet also experience friction on the floor surface in opposite directions (which cancel out, so the lifter is stationary on the ground) :)
kinetic energy and net force
force applies perpendicularly is called thrust force which earths exerts on objests is weight
the weight of the force being applied.
(using squats for the sake of explanation) The lifter exerts an action force on the weight, which is in the opposite direction to gravity. The lifters shoulders also experience the reaction force (from the weight - otherwise, the weight would pass through the lifter or vice versa). The feet of the lift also experience a reaction force, which, combined with the shoulder-reaction force, is equal to the action force (Newton's Third Law). The feet also experience friction on the floor surface in opposite directions (which cancel out, so the lifter is stationary on the ground) :)
(using squats for the sake of explanation) The lifter exerts an action force on the weight, which is in the opposite direction to gravity. The lifters shoulders also experience the reaction force (from the weight - otherwise, the weight would pass through the lifter or vice versa). The feet of the lift also experience a reaction force, which, combined with the shoulder-reaction force, is equal to the action force (Newton's Third Law). The feet also experience friction on the floor surface in opposite directions (which cancel out, so the lifter is stationary on the ground) :)
(using squats for the sake of explanation) The lifter exerts an action force on the weight, which is in the opposite direction to gravity. The lifters shoulders also experience the reaction force (from the weight - otherwise, the weight would pass through the lifter or vice versa). The feet of the lift also experience a reaction force, which, combined with the shoulder-reaction force, is equal to the action force (Newton's Third Law). The feet also experience friction on the floor surface in opposite directions (which cancel out, so the lifter is stationary on the ground) :)
kinetic energy and net force
force applies perpendicularly is called thrust force which earths exerts on objests is weight
the weight of the force being applied.
none. work is done when a force is applied thru a distance. holding something stationary does no work.
none. work is done when a force is applied thru a distance. holding something stationary does no work.
5105.8 J
In 2D, pressure moves in the direction of the force. If the force is an upwards force, it creates an upwards pressure. Your weight is a downwards force and it applies a pressure down onto the floor.
The weight of the mass 'm' is (m g) .That's the minimum force he has to exert in order to balance the force of gravity andlift the weight vertically. If he exerts more force than (mg), the weight will accelerateup, and he'll just wind up either coasting in the middle, or else retarding it at the top.So the eventual outcome is just applying the force (mg) through the distance 'h'.The time taken for the maneuver has no effect on the work done. It's just the amount ofpotential energy gained by the bar-bell due to its increased elevation.Work = [ (force) times (distance) ] or [ (weight) times (height) ].W = m g h
588 W