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A worker applies a 200-n force to a create that he pushes 10m how much work was done?
the amount of work that has been done is 2000 joules!!!!!!!!!!!!!
If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed onto the lower temperature reservoir how much work has been done by the system?
The work done by the system can be calculated by finding the difference between the heat absorbed from the high-temperature reservoir and the heat passed onto the low-temperature reservoir. In this case, the work done by the system is 130 joules (425 joules - 295 joules).
How much power is used when Joules of work are done in 10 seconds?
Power is calculated by dividing the work done in Joules by the time taken in seconds. So, if x Joules of work are done in 10 seconds, the power used would be x/10 watts.
If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed on to the lower temperature reservoir how much work has been done by the system?
To calculate the work done by the system, we can use the formula for efficiency: Efficiency = Work output / Heat input. First, let's determine how much heat is not passed on to the lower temperature reservoir: 425 - 295 = 130 J. Thus, the work done by the system is the heat that is not passed on, which is 130 joules.
How much is done when an 45 N forces moves a block 20 m?
The work done would be 900 joules. Work is calculated by multiplying the force applied (45 N) by the distance over which it is applied (20 m). This gives the work done in joules.
A worker applies a 200-n force to a create that he pushes 10m how much work was done?
the amount of work that has been done is 2000 joules!!!!!!!!!!!!!
If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed onto the lower temperature reservoir how much work has been done by the system?
The work done by the system can be calculated by finding the difference between the heat absorbed from the high-temperature reservoir and the heat passed onto the low-temperature reservoir. In this case, the work done by the system is 130 joules (425 joules - 295 joules).
How much power is used when Joules of work are done in 10 seconds?
Power is calculated by dividing the work done in Joules by the time taken in seconds. So, if x Joules of work are done in 10 seconds, the power used would be x/10 watts.
If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed on to the lower temperature reservoir how much work has been done by the system?
To calculate the work done by the system, we can use the formula for efficiency: Efficiency = Work output / Heat input. First, let's determine how much heat is not passed on to the lower temperature reservoir: 425 - 295 = 130 J. Thus, the work done by the system is the heat that is not passed on, which is 130 joules.
How much is done when an 45 N forces moves a block 20 m?
The work done would be 900 joules. Work is calculated by multiplying the force applied (45 N) by the distance over which it is applied (20 m). This gives the work done in joules.
How much work in joules is done when a force of 14 N moves an object 6 meters?
(14 N x 6 m) = 84 newton-meters = 84 joules
How much power is used when 600 joules of work are done in ten seconds?
The power used would be 60 watts. This can be calculated by dividing the work done (600 joules) by the time taken (10 seconds).
How much power is involved if 1800 joules of work are done in 1 minute?
1800 joules / 1 minute = 1,800 joules / 60 seconds = 30 joules per second = 30 watts.
An electromagnetic force 1 200 N lifts a truck 10 meters How much work was done?
There was 12k Joules of work done.
When moving a couch you exert a force of 400N and push it 4M how much work has been done on the couch?
The work done on the couch is given by the formula: Work = Force x Distance. In this case, the work done is 400N x 4m = 1600 J (joules).
How much power is used (in watts) when 120 joules of work is done in 1 minute?
Power is the rate at which work is done, given by the formula Power = Work/Time. In this case, Power = 120 Joules / 60 seconds = 2 Watts.
How much work is done on a 50 newton rock that you lift 10 meter?
The work done is 500 joules. Work is calculated by multiplying force by distance, which is 50 newtons x 10 meters = 500 joules.
