None. Work is the product of (force) x (distance). If the force doesn't
persist while moving through a distance, then the product is zero.
The answer is 0. If you used the formula of =>mgh, you would get a value which would be wrong. The question is a trick question. There is no work done in 'holding' an object but work would be done in 'lifting' an object. Hence, 0. ~Dartz
No, work is not done when holding an object still. Work is defined as force applied over a distance, so if the object is not moving, no work is being done.
The work done by the end loader holding 1500 kg of sand 2.00 m off the ground does 3000 J of work regardless of the time it holds it. Work is equal to the product of a force on an object, and the distance the force acted on the object.
To increase the gravitational potential energy (GPE) of an object, you can raise it to a higher elevation, where the gravitational force is stronger. This can be done by lifting the object against gravity, increasing its distance from the ground. The formula for gravitational potential energy is GPE = mgh, where m is the object's mass, g is the acceleration due to gravity, and h is the height of the object above a reference point.
Yes, that's correct. Gravitational potential energy increases with height because the higher an object is raised above the ground, the more work has to be done against gravity, resulting in a greater potential energy.
The answer is 0. If you used the formula of =>mgh, you would get a value which would be wrong. The question is a trick question. There is no work done in 'holding' an object but work would be done in 'lifting' an object. Hence, 0. ~Dartz
No, work is not done when holding an object still. Work is defined as force applied over a distance, so if the object is not moving, no work is being done.
No, work is only done when an object is moved.
The work done by the end loader holding 1500 kg of sand 2.00 m off the ground does 3000 J of work regardless of the time it holds it. Work is equal to the product of a force on an object, and the distance the force acted on the object.
Yes assuming that no damage was done to it.
To increase the gravitational potential energy (GPE) of an object, you can raise it to a higher elevation, where the gravitational force is stronger. This can be done by lifting the object against gravity, increasing its distance from the ground. The formula for gravitational potential energy is GPE = mgh, where m is the object's mass, g is the acceleration due to gravity, and h is the height of the object above a reference point.
Yes, that's correct. Gravitational potential energy increases with height because the higher an object is raised above the ground, the more work has to be done against gravity, resulting in a greater potential energy.
To reduce the pressure an object exerts on the ground, you can increase the area over which the force is distributed. This can be done by using wider supports or distributing the weight of the object over a larger surface area. Another way is to decrease the force being applied to the object itself.
It's a play on words (try holding a weight steady at arms length) that's totally dependent on the definition of "work".
A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
The work done in moving a body of mass m to a height h above the ground is given by the equation: work = mgh, where m is the mass of the body, g is the acceleration due to gravity, and h is the height.
Only the component of the force in the direction of the motion of the object counts as work. Work done is defined as the force applied in the direction of the displacement multiplied by the displacement. Perpendicular forces do not contribute to the work done on the object.