Just multiply the force times the distance. The answer is in joules.
The work done is 500 joules. Work is calculated by multiplying force by distance, which is 50 newtons x 10 meters = 500 joules.
The work done to lift the log can be calculated using the formula: Work = Force x Distance. In this case, the force is 5000 N and the distance is 5 meters. Therefore, the work required to lift the log 5 meters would be 5000 N x 5 m = 25000 Joules.
The work done is calculated by multiplying the force applied by the distance over which the force is applied. In this case, the work done to lift the potted plant would be 25 Newtons * 1.5 meters = 37.5 Joules.
The work done is calculated as the force applied multiplied by the distance moved in the direction of the force. In this case, the work done lifting the bag is 45 N * 1.2 m = 54 J, and the work done carrying it is 45 N * 10 m = 450 J. The total work done is the sum of these, which is 54 J + 450 J = 504 J.
A pulley system is used to lift a 2,000 newton engine up a distance of 3 meters. How much force will the operator have to apply if the mechanical advantage of the pulley system is 4? mechanical advantage = 500 newtons.
The work done is 500 joules. Work is calculated by multiplying force by distance, which is 50 newtons x 10 meters = 500 joules.
The work done to lift the log can be calculated using the formula: Work = Force x Distance. In this case, the force is 5000 N and the distance is 5 meters. Therefore, the work required to lift the log 5 meters would be 5000 N x 5 m = 25000 Joules.
200 newton-meters per second = 200 watts.
faggio
The work done is calculated by multiplying the force applied by the distance over which the force is applied. In this case, the work done to lift the potted plant would be 25 Newtons * 1.5 meters = 37.5 Joules.
The work done is calculated as the force applied multiplied by the distance moved in the direction of the force. In this case, the work done lifting the bag is 45 N * 1.2 m = 54 J, and the work done carrying it is 45 N * 10 m = 450 J. The total work done is the sum of these, which is 54 J + 450 J = 504 J.
Weight of a mass of 50 kg = [ m g ] = (50 x 9.8) = 490 newtons.Work = force x distance = 490 x 4 = 1,960 newton meters = 1,960 joules
5.0 meters
A pulley system is used to lift a 2,000 newton engine up a distance of 3 meters. How much force will the operator have to apply if the mechanical advantage of the pulley system is 4? mechanical advantage = 500 newtons.
That depends how high you lift it.The work is mgh (mass x gravity x height). If the mass is in kilograms, gravity is in newton/kilogram (Earth gravity is about 9.8 newton/kilogram), and the height is in meters, then the work will be in joules.
The work done is calculated as the force applied multiplied by the distance moved in the direction of the force. In this case, the work done is (15 , \text{N} \times 3.0 , \text{m} = 45 , \text{J}).
What is the value of Wi? 7,500 joules