Work = Force x distance = 700N x 4m = 2800N•m = 2800 Joules
Work is force x distance = 700 x 4 = 2800 Joules
Work = Force (N) x Distance (m) Therefore, the units of work are N-m, or Newton-meters. F=700N D=4m W=FxD = 700x4 = 2800N-m
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules
The idea here is to multiply the force by the distance.
a fallen treee is lifted 2.75 meters. How much work is done?
Work is force x distance = 700 x 4 = 2800 Joules
Work = Force (N) x Distance (m) Therefore, the units of work are N-m, or Newton-meters. F=700N D=4m W=FxD = 700x4 = 2800N-m
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules
700 x 4 = 2,800 newton-meters = 2,800 joules
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
question 24 on penn foster is C.
The idea here is to multiply the force by the distance.
Work = (force) x (distance) = 7 x 2.4 = 16.8 joules
a fallen treee is lifted 2.75 meters. How much work is done?
2000
Work = force x distance = 20 x 2 = 40 newton-meters = 40 joules
I believe that when you say 'lifted through', you mean lifted to a height of 10m. If so, the amount of work is such: Work= Force x Distance which have the units (Joules = Newtons x meters) When the object is lifted, it increases in its potential energy. The equation for this is: Potential energy = mass x gravitational force x height = 4.5 x 9.81 x 10 =441.45 Joules As 1 joule = 1 newton x meters and we have 441.45 Joules, 441.45 joules of works is done! :D