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The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.
What else can I help you with?
How much work is done when a 1N mass is raised a vertical distance of 1 m?
The work done is 1 Joule. Work is calculated by multiplying force (1N) by the distance moved (1m) in the direction of the force.
What is the formula for work done against gravity?
Work Done = Force x Distance = Power / Time = (Force x speed)/Time
Would you do more work lifting a box from the floor to the top of a table or from the floor to a shelf above your head?
Work is done by a force acting on a mass when that mass is displaced (moved).Basically, more work is required to move a mass through a greater distance, similarly more work is required to move a greater mass though the same distance.Providing all other things are equal, if the same box is moved through a distance of two metres you do more work than moving the box through one metre.
What amount of work is done when a force F is used to raise a 4-kg mass m from the ground to a height of 5 m?
The amount of work done is equal to the force applied multiplied by the distance the object is raised. In this case, the work done is equal to the force F multiplied by the height of 5 meters.
When is work said to be done against the force of gravity?
All bodies with mass are attracted to the Earth by gravity, so when a body is raised you must do work to raise it. This work is equal to force x height, if force is in Newtons and height in meters, the work is in units of Joules.
How much work is done when a 1N mass is raised a vertical distance of 1 m?
The work done is 1 Joule. Work is calculated by multiplying force (1N) by the distance moved (1m) in the direction of the force.
What is the formula for work done against gravity?
Work Done = Force x Distance = Power / Time = (Force x speed)/Time
A crane does 5000J of work to lift a box a vertical distance of 16.0 m Calculate the mass of the box?
Force on the box = (weight) = (mass) x (gravity)Work = (force) x (distance) = (mass x gravity) x (distance)Mass = (work) / (gravity x distance)= (5000) / (9.8 x 16) = 31.888 kg (rounded)
Would you do more work lifting a box from the floor to the top of a table or from the floor to a shelf above your head?
Work is done by a force acting on a mass when that mass is displaced (moved).Basically, more work is required to move a mass through a greater distance, similarly more work is required to move a greater mass though the same distance.Providing all other things are equal, if the same box is moved through a distance of two metres you do more work than moving the box through one metre.
A stone of mass falls freely through a vertical distance it's kinetic energy will be?
mgh or (1/2)mv2
How much work is done when vertical force acts on an object moving horizontally?
It depends on the magnitude of the force and the mass of the object
How much work is done when a vertical force acts on a moving object horizontally?
It depends on the magnitude of the force and the mass of the object
What amount of work is done when a force F is used to raise a 4-kg mass m from the ground to a height of 5 m?
The amount of work done is equal to the force applied multiplied by the distance the object is raised. In this case, the work done is equal to the force F multiplied by the height of 5 meters.
When is work said to be done against the force of gravity?
All bodies with mass are attracted to the Earth by gravity, so when a body is raised you must do work to raise it. This work is equal to force x height, if force is in Newtons and height in meters, the work is in units of Joules.
How much work is done when 1kg is raised a vertical distance of 1 m?
W = mgh m = mass g = gravitational acceleration h = height m = 1 kg g = 9.8 m/S2 h = 1 metre W = 1x 9.8 x 1 = 9.8 N
What is the center of mass of semicircle?
The center of mass of a uniform semicircle lies along its axis of symmetry, which is the vertical line through its flat edge. Specifically, for a semicircle of radius ( R ), the center of mass is located at a distance of ( \frac{4R}{3\pi} ) from the flat edge along the vertical axis. This position accounts for the distribution of mass in the semicircular shape.
How do you solve for power if mass distance and time is given?
power=work done/time interval
