The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.
The work done is 1 Joule. Work is calculated by multiplying force (1N) by the distance moved (1m) in the direction of the force.
Work Done = Force x Distance = Power / Time = (Force x speed)/Time
Work is done by a force acting on a mass when that mass is displaced (moved).Basically, more work is required to move a mass through a greater distance, similarly more work is required to move a greater mass though the same distance.Providing all other things are equal, if the same box is moved through a distance of two metres you do more work than moving the box through one metre.
The amount of work done is equal to the force applied multiplied by the distance the object is raised. In this case, the work done is equal to the force F multiplied by the height of 5 meters.
All bodies with mass are attracted to the Earth by gravity, so when a body is raised you must do work to raise it. This work is equal to force x height, if force is in Newtons and height in meters, the work is in units of Joules.
The work done is 1 Joule. Work is calculated by multiplying force (1N) by the distance moved (1m) in the direction of the force.
Work Done = Force x Distance = Power / Time = (Force x speed)/Time
Force on the box = (weight) = (mass) x (gravity)Work = (force) x (distance) = (mass x gravity) x (distance)Mass = (work) / (gravity x distance)= (5000) / (9.8 x 16) = 31.888 kg (rounded)
Work is done by a force acting on a mass when that mass is displaced (moved).Basically, more work is required to move a mass through a greater distance, similarly more work is required to move a greater mass though the same distance.Providing all other things are equal, if the same box is moved through a distance of two metres you do more work than moving the box through one metre.
mgh or (1/2)mv2
It depends on the magnitude of the force and the mass of the object
It depends on the magnitude of the force and the mass of the object
The amount of work done is equal to the force applied multiplied by the distance the object is raised. In this case, the work done is equal to the force F multiplied by the height of 5 meters.
All bodies with mass are attracted to the Earth by gravity, so when a body is raised you must do work to raise it. This work is equal to force x height, if force is in Newtons and height in meters, the work is in units of Joules.
W = mgh m = mass g = gravitational acceleration h = height m = 1 kg g = 9.8 m/S2 h = 1 metre W = 1x 9.8 x 1 = 9.8 N
The center of mass of a uniform semicircle lies along its axis of symmetry, which is the vertical line through its flat edge. Specifically, for a semicircle of radius ( R ), the center of mass is located at a distance of ( \frac{4R}{3\pi} ) from the flat edge along the vertical axis. This position accounts for the distribution of mass in the semicircular shape.
power=work done/time interval