That depends also on the direction of force, though it simplifies greatly if force is all the way applied exclusively in the direction of movement.
Work doesn't depend on the mass too.
Formula is(assuming the direction of applied force is the same as of displacement):
W = F * r, where
W - work,
F - force,
r - displacement.
For given data, it will be:
W = 20 * 15 = 300 J
The force Rudolph exerts is equal to the mass of the sleigh multiplied by the acceleration, which is 50kg * 2m/s^2 = 100N.
About 110.2 pounds.
The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).
The work done to lift a weight is given by the formula: work = force x distance. In this case, the force is equal to the weight of the object (50kg x 9.8 m/s^2 = 490 N), and the distance is 3.0m. Therefore, the work required to lift a 50kg weight 3.0m is 1470 joules.
Multiply the force by the distance. The mass is irrelevant for this problem.
400 J
The force Rudolph exerts is equal to the mass of the sleigh multiplied by the acceleration, which is 50kg * 2m/s^2 = 100N.
About 110.2 pounds.
If a force of 20 N acts through a distance of 15 m, then it does (20 x 15) = 300 joules of work.The other facts of the case, such as the mass of the crate being pushed, don't matter.
compression is the force pushed on and object. The formula for how much pressure during compression is: force/area.
The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).
50kg
2.2Kg= 1lb divide 50Kg by 2.2 to get pounds
120lbs or 50kg.
50kg
The work done to lift a weight is given by the formula: work = force x distance. In this case, the force is equal to the weight of the object (50kg x 9.8 m/s^2 = 490 N), and the distance is 3.0m. Therefore, the work required to lift a 50kg weight 3.0m is 1470 joules.
Multiply the force by the distance. The mass is irrelevant for this problem.