air resistance will increase the time for an object to fall to the ground
Decreasing the length or increasing the thickness of the wire would cause its resistance to decrease.
Vasoconstriction would have a greater effect on increasing vascular resistance compared to vasodilation. When blood vessels constrict, their diameter decreases, leading to increased resistance to blood flow. Conversely, vasodilation results in an expansion of blood vessel diameter, reducing resistance.
As long as the voltage between the ends of the circuit remains constant, the current through the circuit is inversely proportional to the total effective resistance of the circuit.
Increasing the friction on the pulley axles or increasing the tension in the rope running through the pulleys would increase the resistance of the pulleys. Alternatively, adding more weight to the load being lifted by the pulleys would also increase the resistance.
Resistance is defined by R = V/I where V is potential difference and I is current. It is not: change in pd / change in current - which would be the gradient of the curve. Thus to measure the resistance at a particular pd we simply read off the current at that pd and use the equation above. The problem stems from the way resistors are introduced before non-ohmic components, and for ohmic components it may appear that the gradient is being used for the resistance.
Something that helps to make up the final results of an experiment, and taking it away or adding stuff on to it would therefore change the final results of the experiment.
Adding calcium chloride to sodium carbonate would be a chemical change because it results in the formation of new substances (calcium carbonate and sodium chloride) with different chemical properties than the original reactants.
no, it would change its charge not its mass.
Decreasing the length or increasing the thickness of the wire would cause its resistance to decrease.
yes.because adding heat would increase the Products and lowering the Reactants.
The resistance remains constant. The voltage would change, in accordance with Ohms' law, with a change in current.
Adding more DPIP to each tube would likely result in a faster color change, as more DPIP molecules would be available to accept electrons from the reduced chloroplasts. This would lead to a quicker reduction of DPIP and a faster transition from blue to colorless, indicating a higher rate of photosynthesis.
For example adding a base.
If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.
The performance results would decline, but the selection process would remain the same
A item's resistance is not able to be changed with water. Water on an object or absorbed by an object can change the overall resistance of an object by putting in parallel the resistance of the water itself. If you were to use very clean water that was deionized and soaked your device, you would see no resistance change.
Adding more DPIP to each experimental tube would likely result in a faster rate of color change or a more pronounced color change in the experiment. DPIP is a redox indicator that changes color as it accepts electrons during the photosynthetic process. Increasing the amount of DPIP can make the color change more noticeable due to a higher concentration of the indicator molecule being reduced.