To calculate acceleration when braking, we need more information such as the initial speed. Given that the braking time is 4 seconds and the final speed (0 rpm) is 2400 rpm, we can find the acceleration. The magnitude of acceleration can be determined using the formula: acceleration = (final velocity - initial velocity) / time.
Gearing down increases the engine's revolutions per minute (RPM) and torque, but decreases the speed of the car. This allows the engine to work at a more efficient RPM range for the desired speed or acceleration.
When the load on the engine is increased, the engine RPM typically decreases because the engine has to work harder to overcome the additional resistance. This is due to the increased demand for power output to maintain the same speed or acceleration.
Torque is equal to friction force (F) * radius (r). Torque is also equal to moment of inertia (I) * Angular acceleration (a). Angular acceleration is equal to rotational velocity * 2Pi/time, which is 2 seconds. So, F = IRa/r, or 45.63 Newtons
Yes, a higher gear ratio is generally better for improving a vehicle's performance as it allows the engine to operate at a higher RPM, providing more power and acceleration.
The main difference between a 15K RPM (Revolutions Per Minute) and a 7.2K RPM drive is the speed at which the disk spins. A 15K RPM drive spins at a faster rate than a 7.2K RPM drive, resulting in quicker data access and transfer speeds. However, a 15K RPM drive may generate more noise and heat compared to a 7.2K RPM drive.
Horsepower: 140 @ 3800 RPM torque : 215 @ 2400 RPM
260 hp @ 5000 rpm 330 tq @ 2400 rpm
245 Horsepower @4400 rpm and 345 ft lb torque @2400 rpm
My Chilton book shows ( 170 horsepower at 3800 RPM and 270 ft-lbs torque at 2400 RPM )
The operating range of rpm, for a C 12 Caterpillar diesel engine is 800 RPM to a maximum of 2400 RPM. The engine should be run at no more than 1800 RPM for a long period of time.
That depends what you want to compare. In any case, 3G is more acceleration than 1G.
120 horsepower at 4400 RPM and 190 ft/lbs torque at 2400 RPM
250 HP @ 4400 rpm, 350 ft lbs torque @ 2400 rpm.
as for crankshaft rotates for a certain rpm ...... and with respective rpm we need it to come to rest and the brake applied to it with much power..... determines how much power we need to stop it at a certain rpm..... these brake power is known as brake horse power..
2.2 vin 4, 130 ft-lbs. @ 2800 rpm4.3 vin W (Vortec), 235 ft-lbs. @ 2400 rpm 4.3 vin Z, 235 ft-lbs. @ 2400 rpm
My 115 EFI mercury outboard would only generate 4200 RPM. The power gradually reduced and finally levelled off at 2400 RPM. I have had other problems in the past relating to power settings. Fuel injectors and impellor have been eliminated as potential causes.
According to my Chilton repair manual : 160 hp @ 4200 RPM / 220 ft.lbs torque @ 2400 RPM (Helpfull)