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Well, isn't that just lovely? To find the power, we use the formula P = W/t, where P is power, W is work, and t is time. So, if 600 J of work is done in 3 seconds, we simply divide the work by the time to get the power. In this case, 600 J divided by 3 s equals 200 watts of power. Just like that, we've painted a beautiful picture of power calculation!

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BobBot

6mo ago

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How much power is used when 600 joules of work are done in ten seconds?

The power used would be 60 watts. This can be calculated by dividing the work done (600 joules) by the time taken (10 seconds).


How much power is used when 600 J of work are done in 10?

610


If 600 watts of power are used in 45 seconds how much work was done?

The work done can be calculated using the formula: Work = Power x Time. Plugging in the values, we get Work = 600 watts x 45 seconds = 27,000 joules. Therefore, 27,000 joules of work was done.


How much power is used when 600 J of work are done in 10 seconds?

The power used would be 60 watts. This can be calculated by dividing the work done (600 J) by the time taken (10 seconds), resulting in 60 watts.


How much power is used when 600 J of work is done in 10 S?

610


How power is used when 600 J of work are done in 10S?

Power is calculated by dividing the work done by the time taken, so in this case it would be ( \frac{600 \text{ J}}{10 \text{ s}} = 60 \text{ W} ). This means that the power used in this scenario is 60 Watts.


How much power is used when 600j of work is done in 10 s?

Well, isn't that just a happy little question! To find the power used, you simply divide the work done (600 Joules) by the time taken (10 seconds). So, 600 Joules of work done in 10 seconds means the power used is 60 Watts. Just like painting a beautiful landscape, it's all about finding the right balance and enjoying the process.


How much power is used when 600 j of are done in 10 s?

610


How much power is needed to perform 600 Joules of work in 150 seconds?

Power = Work / time= 600 J / 150 secPower = 4 J/s or 4 Watts (1 Watt = 1 J/s)


If it takes 600 N of force to move a stalled truck 30 meters and you do it in 15 seconds what is your power?

The work required to move the truck is 600 N (600 kg-m/sec2) times 30 meters = 18000 joules. If this is done in 15 seconds, the average power was 1200 watts (kg-m2/sec3).


What amount of work can a 600 W motor do in 4 minutes?

(600 Watts) x (4 minutes) = (600 joules per second) x (240 seconds) = 144,000 joules =144 kilojoules


How much power is required to push a box 4.0 m with a force of 150 N in 2.5s?

The work done in moving the box can be calculated as force times distance, which is 150 N * 4.0 m = 600 J. The power can then be calculated as work done divided by time taken, which is 600 J / 2.5 s = 240 W. Hence, 240 Watts of power is required to push the box.