gravity = 9.8 m/s2 , 3 x 9.8 = 29.4 m/s (excluding air resistance)
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
No, both balls will hit the ground at the same time, assuming they are dropped from the same height and in a vacuum. The horizontal velocity does not affect the time it takes for an object to fall vertically due to gravity.
To measure the amount of kinetic energy, you would need a measuring tape or ruler to determine the height from which the balls are dropped, a timer to measure the time taken for the balls to reach the ground, and a scale to measure the mass of the balls. The kinetic energy can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the ball and v is the velocity it reaches upon impact.
If we can ignore the effects of air resistance and consider gravity only, then thehorizontal component of velocity has no effect on the vertical component.These balls accelerate vertically at the same rate, and hit the ground at the same time.In an extreme case, the same is true of a shot fired from a gun and one dropped fromthe muzzle at the same time.
The basic equation for average velocity is distance over time. However, if the velocity is changing uniformly, as it is in free fall, you can use initial velocity plus final velocity divided by two. That makes this problem easy. In free fall the object accelerates at 9.8 m/ss. That means every second it picks up 9.8 m/s of speed. So if is dropped from rest, then one second later its speed will be 9.8 m/s. Its average speed during that time is then initial velocity = 0 plus final velocity = 9.8 divided by 2, to get ; 4.9 m/s.
This is an old experiment. Neither. Both balls have the same velocity as gravity draws on them equally.
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
No, both balls will hit the ground at the same time, assuming they are dropped from the same height and in a vacuum. The horizontal velocity does not affect the time it takes for an object to fall vertically due to gravity.
naw
doubt it
I like turtles.
Galilieo. He dropped it from the leaning tower of Pisa. In ITALY,
Because her balls have dropped
To measure the amount of kinetic energy, you would need a measuring tape or ruler to determine the height from which the balls are dropped, a timer to measure the time taken for the balls to reach the ground, and a scale to measure the mass of the balls. The kinetic energy can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the ball and v is the velocity it reaches upon impact.
The duration of Bowling Balls is 1320.0 seconds.
The duration of Golden Balls is 3600.0 seconds.
the year when my balls dropped.