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If a 150 lbm swimmer is floating in a nearby pool and 5 percent of her body volume is above the surface of the water then what is the swimmers density?
Wiki User
∙ 14y ago
The density of water depends on its temperature, but as you didn't give a temperature and for simplicity sake here we will take the density of water to be 1g/cm3.
We will also consider the density of the swimmer to be uniform, else we will have to get into a serious discussion about anatomy.
Lets convert 150 lbs. into grams --->
150 lbs *453.59237 g/lb = 68038.8555 grams
In order to counter this mass 68038.8555 grams of water is going to have to be displaced. This will be a volume of 68038.8555 cm3.
95% of the swimmers volume = 68038.8555 cm3
so
.95x = 68038.8555 cm3. x= 71619.8479 cm3 where x is the total swimmer's volume.
density is Mass/Volume
so
Swimmer's density is 0.949 g/cm3 or 0.949 g/ml
Wiki User
∙ 14y ago
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