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A projectile is fired horizontally from a gun that is 71.0 m above flat ground emerging from the gun with a speed of 250 ms What is the magnitude of the vertical component of its velocity as it st?
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
Sketch velocity-time graph when an object is thrown vertically upward?
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
What is an example problem of speed and velocity?
An example problem involving speed is calculating the average speed of a car that travels 100 miles in 2 hours. An example problem involving velocity is determining the velocity of a ball thrown upward with an initial velocity of 20 m/s at a height of 40 meters above the ground.
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Bullet fired w certain velocity at angle above the horizontal at location where g is 10 m a sec2 The initial x and y comp. of its velocity are 86.6 ms and 50.0 ms how long to reach highest trajectory?
The question is already resolved into horizontal and vertical components for us.This is a very thoughtful and considerate favor, because now, we can completelyignore the horizontal details.-- The bullet is fired with an initial vertical velocity component of 50.0 meters/second.-- The bullet will continue ascending for 50.0/10 = 5.00 seconds, before itruns out of gas, surrenders to gravity, and begins to descend.Additional factoids that emerge from the work but are not required for full crediton the exam question:-- The gun is aimed 30 degrees above the horizontal, and the bullet leaves it at 100 meters/second.-- The highest altitude above ground achieved by the bullet is (125 meters) + (altitude of the gun muzzle).-- Horizontal distance the bullet travels at or above the altitude of the gun muzzle is(86.6 m/s) x (10 sec) = 866 meters. -- The Earth's curvature, and the effects of air resistance, are ignored to makethe calculation easier.-- We're dealing with a very slow bullet here. Even the mild-mannered 22-caliber"Short round" , with a 1.9-gram bullet and either a small amount of gunpowderor none at all, intended only for indoor training or target practice, has a typicalmuzzle velocity of around 210 meters/second ... double that of the fearsomeprojectile described in the question.
A projectile is fired horizontally from a gun that is 71.0 m above flat ground emerging from the gun with a speed of 250 ms What is the magnitude of the vertical component of its velocity as it st?
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
How do you calculate result?
AccelerationStep 1 Find the acceleration of the object, the time the object is being accelerated and the initial velocity. These values are usually given to you in the problem. If the force is given, find the acceleration by dividing the force on the object by its mass.Step 2 Convert all units to standard units. Acceleration should be in meters per second squared. Velocity should be in meters per second, and time should be in seconds.Step 3 Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.Step 4 Add this velocity to the initial velocity. In the example above, if the object had an initial velocity of 5 meters per second, the resultant velocity would be 34.4 meters per second. The overall formula here is v (final) - at + v (initial) where "v" is velocity, "a" is acceleration and "t" is time. In this example the equation would look like this: v (final) = 9.8 x 3 + 5, giving us a result of 34.4.After ImpactStep 1 Identify the initial velocity of the two objects, the mass of both objects and the final speed of either object if it is given. These values are usually given in the problem.Step 2 Convert all velocities to meters per second and all masses to kilograms.Step 3 Multiply the initial velocity of each object by its mass. Add these two products together to get the total momentum. For example, if both objects have a mass of 5 kilograms, one is at rest and the other is moving at 10 meters per second. The calculation would look like this: 5 x 10 + 5 x 0. This would give us a result of 50 kilogram-meters per second.Step 4 Divide the total momentum by the sum of the masses if the two objects stick together after impact. This will give you the resultant velocity of the two objects. In the example above, we would take 50 and divide by the sum of the masses, which is 10, getting a result of 5 meters per second.If the objects do not stick together, subtract the product of the mass and the final velocity of one object from the total initial momentum. Then, divide the difference by the mass of the other object. This will give you the resultant velocity of the other object. In the example from the previous step, if the final velocity of the object originally moving at 10 meters per second was 2 meters per second, our calculation would look like this: (50 - 10) / 5, which gives us a result of 8 meters per second.
Whats the equation for acceleration?
Acceleration=force divided by mass. The above is Newtons second law. Acceleration is also the change in velocity over the change in time, so it can also be stated as a=(final velocity - initial velocity)/(elapsed time)
When a ball is thrown vertically upward at initial velocity of 15 meter per second Find the position and velocity after 1.0 second and 40 second after leaving your hand?
1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.
Which information is needed to find the time a projectile is in motion?
The object's initial distance above the ground The object's initial velocity
How to Calculate the terminal velocity?
Terminal velocityThere is more than one explanation for terminal velocity, I think you are asking about a person or skydiver as opposed to a bullet.Terminal velocity is the velocity reached when the drag force equals the weight of the body minus the buoyant force, which halts acceleration and causes speed to remain constant.the terminal velocity of a skydiver in a normal freefall position with a closed parachute is about 120 mph or 54 m/s. This velocity is the asymptotic limiting value of the acceleration process, since the effective forces on the body more and more closely balance each other as it is approached. In this example, a speed of 50% of terminal velocity is reached after only about 3 seconds, while it takes 8 seconds to reach 90%, 15 seconds to reach 99% and so on.
If a ball is thrown at an angle of 40 degrees above the horizontal at a speed of 16 meters per second from the top of a 12.4 m tall building what is the maximum height of the ball above the ground?
The maximum height of the ball above the ground can be calculated using the vertical component of the initial velocity. Assuming no air resistance, the formula to determine maximum height is h = (v^2 sin^2(theta)) / (2g), where v is the initial velocity (16 m/s), theta is the angle (40 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, you can find that the maximum height of the ball is approximately 14.1 meters.
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Sketch velocity-time graph when an object is thrown vertically upward?
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
What is an example problem of speed and velocity?
An example problem involving speed is calculating the average speed of a car that travels 100 miles in 2 hours. An example problem involving velocity is determining the velocity of a ball thrown upward with an initial velocity of 20 m/s at a height of 40 meters above the ground.
How do you work out height from initial velocity final velocity mass and work done?
If you throw an object up, and assume that air resistance is negligible, knowing the initial velocity is enough. One way to do this is to use conservation of energy. Calculate the energy from the initial velocity, then insert it in the formula for gravitational potential energy.Same for final velocity - the final speed is the same as the initial speed. If you know the work done, you already have the first half of the above steps solved.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
