if vigorous enough to create heat the balloon will expand.
When a balloon is squeezed to half its volume at constant temperature, the air pressure inside the balloon increases. This is because the number of air molecules remains constant while the volume decreases, leading to the molecules being packed closer together and increasing the pressure.
If a balloon is heated, the temperature inside the balloon increases, causing the air molecules to move faster and collide more frequently with the walls of the balloon. This increase in collisions leads to an increase in pressure inside the balloon, assuming the volume remains constant according to the ideal gas law (P1/T1 = P2/T2).
The air pressure inside the balloon will increase when it is squeezed to half its volume at constant temperature. This is because the volume of the balloon decreases, leading to the air molecules being more confined in a smaller space, resulting in higher pressure.
Pressure increases.Take a look at the relationship:PV=nRTR is a constant. n is the amount of gas, which would be held constant in a sealed balloon. So:P1 V1 / T1 = P2 V2 / T21- before2- afterThis algebraic equation can help predict the outcome of other cases as well.taking just the balloon first, it is a solid body(flexible), on heating it undergoes cubical expansion, so the first thng that happens is the container(balloon) expands so untill a particular expansion of it the volume of air inside increases(gases dont have a fixed volume) they occupy the area they have .
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
When a balloon is squeezed to half its volume at constant temperature, the air pressure inside the balloon increases. This is because the number of air molecules remains constant while the volume decreases, leading to the molecules being packed closer together and increasing the pressure.
When a balloon is heated, the molecules inside gain kinetic energy and move faster. This causes the molecules to push against the walls of the balloon more vigorously, increasing the pressure inside the balloon. If the balloon is heated too much, it can expand or even burst due to the increased pressure.
If a balloon is heated, the temperature inside the balloon increases, causing the air molecules to move faster and collide more frequently with the walls of the balloon. This increase in collisions leads to an increase in pressure inside the balloon, assuming the volume remains constant according to the ideal gas law (P1/T1 = P2/T2).
The air pressure inside the balloon will increase when it is squeezed to half its volume at constant temperature. This is because the volume of the balloon decreases, leading to the air molecules being more confined in a smaller space, resulting in higher pressure.
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
Pressure increases.Take a look at the relationship:PV=nRTR is a constant. n is the amount of gas, which would be held constant in a sealed balloon. So:P1 V1 / T1 = P2 V2 / T21- before2- afterThis algebraic equation can help predict the outcome of other cases as well.taking just the balloon first, it is a solid body(flexible), on heating it undergoes cubical expansion, so the first thng that happens is the container(balloon) expands so untill a particular expansion of it the volume of air inside increases(gases dont have a fixed volume) they occupy the area they have .
When the internal pressure in a balloon falls, the balloon get smaller and less buoyant.
it dies
Pressure increases.Take a look at the relationship:PV=nRTR is a constant. n is the amount of gas, which would be held constant in a sealed balloon. So:P1 V1 / T1 = P2 V2 / T21- before2- afterThis algebraic equation can help predict the outcome of other cases as well.taking just the balloon first, it is a solid body(flexible), on heating it undergoes cubical expansion, so the first thng that happens is the container(balloon) expands so untill a particular expansion of it the volume of air inside increases(gases dont have a fixed volume) they occupy the area they have .
due to pressure inside the balloon, will be higher because the balloon will try to get smaller and thus the balloon will ascent due to the low density of the helium inside the balloon.
When a balloon has a leak, the pressure inside the balloon decreases as the gas molecules escape through the leak. This results in the balloon deflating and becoming smaller in size.