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Average acceleration is a change in velocity over a period of time:

a = Δv/Δt

"a car is traveling 100 km/hr and comes to a stop..." implies that its original speed, let's call it v_0, was given by:

v_0 = 100 km / 1 hr
= 100,000 m / 3600 s
= 27.77... m/s

and its final velocity, called v_f, is

v_f = 0.

so Δv, the CHANGE in velocity, was v_f - v_0, or

Δv = 0 - 27.77... = -27.77... m/s

and Δt, the change in time, was "3 min[utes]."

Δt = 3 minutes
= 180 s

so

a = Δv/Δt
= (-27.77... m/s) / 180s
= -0.1543 m/s/s

Note that I arbitrarily chose to assign the car's initial velocity a positive sign.

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Q: If a car is traveling 100 km h and comes to a stop in 3 min what is the car's acceleration?
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