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If a person has a mass of 60 kg and velocity of 2 ms what is magnitude of his momentum?
The momentum of an object is given by the product of its mass and velocity. Thus, the magnitude of the person's momentum would be 120 kg·m/s (60 kg * 2 m/s).
If a person has a mass of 60 kg and a velocity of 2 m's what is the magnitude of his momentum?
The momentum of an object is calculated as the product of its mass and velocity. In this case, the momentum would be 60 kg * 2 m/s = 120 kg*m/s.
Does a still object have momentum?
yes , look at a moving car or a walking person
How much momentum does and object have when it stops?
The Same! The statement above is true depending on what u mean. Think of it as a person running. While the person is running they have momentum ( momentum is mass times velocity). Now say they for some reason have to suddenly stop all at once, at the exact moment they stop the momentum is the same, this is why their body would jerk forward. However after that, when they were no longer moving, they would no longer have momentum, mathematically speaking that person's mass times their velocity of zero is then zero.
What is the velocity of a person who runs 500m in 60s?
His speed is (500/60) m/s = 8-1/3 m/s .His velocity can't be completely specified using the information in the question.Its magnitude is 8-1/3 m/s. But in order to also state the direction of his velocity,we would also need to know the direction of his velocity.
If a person has a mass of 60 kg and velocity of 2 ms what is magnitude of his momentum?
The momentum of an object is given by the product of its mass and velocity. Thus, the magnitude of the person's momentum would be 120 kg·m/s (60 kg * 2 m/s).
If a person has a mass of 60 kg and a velocity of 2 m's what is the magnitude of his momentum?
The momentum of an object is calculated as the product of its mass and velocity. In this case, the momentum would be 60 kg * 2 m/s = 120 kg*m/s.
A person is riding a bike at 5 m's due west The mass of the rider plus bike is 95 kg What is the magnitude of its momentum?
Momentum = mass x velocity Assuming you mean the rider is riding at 5 m/s, the momentum is 95 x 5, which is 475 kg-m/s
Does a still object have momentum?
yes , look at a moving car or a walking person
How much momentum does and object have when it stops?
The Same! The statement above is true depending on what u mean. Think of it as a person running. While the person is running they have momentum ( momentum is mass times velocity). Now say they for some reason have to suddenly stop all at once, at the exact moment they stop the momentum is the same, this is why their body would jerk forward. However after that, when they were no longer moving, they would no longer have momentum, mathematically speaking that person's mass times their velocity of zero is then zero.
What is the momentum of an 80 kilogram person if they are running at 6 meters per second?
Momentum (p) = mass * velocity = 80 * 6 = 480 kg-m
What is the momentum of 80 kg person moving southward at 4 ms?
Just multiply mass x velocity.
What is the momentum of a 37kg person riding south on an 18kg bicycle at 1.2 meters per sec?
Linear momentum is defined as mv, where m is the mass and v is the velocity. To get the mass, simply add up the 37kg person and the 18kg bicycle. This makes 55 kg total. We multiply this by 1.2 meters per second. This equals 66kgm/s(Kilogram meters per second).
Why is it harder to stop a four person bobsled than a three person bobsled?
The four bobsled is heavier and has a greater mass. There will be more momentum, leading to greater velocity making it harder to stop.
What is the velocity of a person who runs 500m in 60s?
His speed is (500/60) m/s = 8-1/3 m/s .His velocity can't be completely specified using the information in the question.Its magnitude is 8-1/3 m/s. But in order to also state the direction of his velocity,we would also need to know the direction of his velocity.
When a person jumps from a tree to the ground what happens to the momentum of the person upon landing on the ground?
The momentum of the person is transferred to the ground upon landing. Initially, the person has momentum due to their motion in the air, and upon landing, this momentum is imparted to the ground as the person comes to a stop.
Newton's third law states?
Newton's third law is..."For every action there is an equal and opposite reaction."This is probably the hardest law to really understand.It really helps to understand this law if you understand that the law has its origin in the conservation of momentum principle.The fact of the matter is, force can be most fundamentally understood to be the rate of change of momentum.Let me explain why.First momentum is..P=mvNow look at the equation for force.F=maIt is very similar except that in place of P we have F and in place of v we have a.Looking at the force equation again..f=mawe note that acceleration is the rate of change of velocity so...F=m dv/dtNow since the mass, m, is constant we can put it directly beside the velocity like so..F=d(mv)/dtThis is looking more like the below momentum equation...P=mvThe only difference is that for the momentum equation, we have, mv, and for the force equation we have the rate of change of, mv, or, d(mv)/dtNow in the force equationF=d(mv)/dtbecause P = mv, we can replace, mv with P...F=dP/dtAs I said, force is the rate of change of momentum.Now since the law of conservation of momentum states that momentum is neither created nor destroyed, if an object picks up momentum, another object to lose momentum. In Newton's third law the "action" force is the second body picking upmomentum and the "reaction" force is the first body losing that momentum.As an example, imagine two people standing on a very slippery skating rink, because they are standing still, together, they have zero momentum. If one person pushes the second person, or "applies a force" on the second person, the second person has momentum delivered to them and that second person picks up speed/momentum in that direction. The first person however picks up speed/momentum in the other direction, which means that he also had momentum delivered to him. That second person picking up momentum was the "action force", and that first person picking up momentum in the other direction was the "reaction force".The second person picked up momentum in one direction, and since there is the conservation of momentum law, the first picked up momentum in the opposite direction. Their momentum was zero before the event and since momentum has direction the sum of both momenta add up to zero after the event.If both people had been moving, for example, to the right and the first person pushed the second person also to the right, the second person would have picked up momentum to the right and the first person would have only lost momentum to the right. There would have still been both an action and a reaction force however because momentum was only exchanged.
