If a rocket accelerates from rest at a rate of 50 mss for 10s what distance it will cover during this time is?

Answer 1

3000m/s

Answer 2

The distance covered by the rocket can be calculated using the equation (d = \frac{1}{2} \times a \times t^2), where (a) is the acceleration and (t) is the time. Plugging in the values, we get (d = \frac{1}{2} \times 50 ,m/s^2 \times (10 s)^2 = 2500 ,m). So, the rocket will cover a distance of 2500 meters during this time.

Answer 3

2500 m