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There is an equation which states:

S=V0t+1/2*at2

S is the distance

V0 is the initial velocity

t is time taken

a is acceleration

In your case,

S=V0t+1/2*at2

4,9=0*t+1/2*9,8*t2

4,9/4,9=t2

1=t2

t=1 second

You can calculate the final velocity with simple equation

a=V2-V1/t

9,8=V2/1

V2=9,8m/s2

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Q: If a stone is dropped from the edge of the roof how long does it take to fall 4.9m and what is its speed at the end of that fall?
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