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Given f = 15 cm. Magnification = 3. So the ie v/u = 3. So v = 3u

Using lens formula, 1/f = 1/v - 1/u

Now u = -u and v = -3u and f = 15

Plug these.

1/15 = -1/3u + 1/u

Hence u = 10 cm.

The object is to be placed at a distance of 10 cm from the lens.

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How do images form in concave?

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