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Given f = 15 cm. Magnification = 3. So the ie v/u = 3. So v = 3u

Using lens formula, 1/f = 1/v - 1/u

Now u = -u and v = -3u and f = 15

Plug these.

1/15 = -1/3u + 1/u

Hence u = 10 cm.

The object is to be placed at a distance of 10 cm from the lens.

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Wiki User

12y ago
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Nawaf Alasmari

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2y ago

تبنبنبنبخببخبولملخلمثوثهبخدخدخددنخيبخبوولندندنبميخ

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Oluwaseyi Alaya

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2y ago
i DONT UNDERSTAND WHAT YOU WROTE

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Bobola

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2y ago

-6 cm

Using

f = (uv) / (u+v)

Where u = object distance

v =image distance

f = focal lenght

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Viva Bashirian

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2y ago
im not sure this is right...

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Wiki User

14y ago

30 cm

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Q: If a virtual image is formed along the principal axis 10 cm from a concave mirror with the focal length 15 cm what is the object distance from the mirror?
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