Gravitational force decreases as the square of distance. In this case, the force
has decreased by 200 N / 50 N = 4. Therefore, the distance must be sqrt (4) = 2
times what it was. It was R before, then it must be 2R now.
Zero gravity does not occur at a specific distance from the Earth's surface. The sensation of weightlessness experienced by objects or astronauts in space is due to being in free fall towards Earth while moving forward with enough velocity to stay in orbit. This can happen at various distances from the Earth's surface, depending on the object's speed and trajectory.
gravity is the force by which the earth or any heavenly body attracts a mass towards its centre. the gravitational force depends on the mass of the heavenly body and the mass of the other body on which it acts. the gravitational force of the earth is 9.8 newtons. on a mass of 7 kgs on earth,the force would be 9.8 by 7 that is 68.6 newtons.
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
The radius of curvature is the distance from the center of a curved surface or lens to a point on the surface, while the center of curvature is the point at the center of the sphere of which the curved surface is a part. In other words, the radius of curvature is the length of the line segment from the center to the surface, while the center of curvature is the actual point.
The distance of the principal focus from the optical center is called the focal length.
Approximately 6370km
The force due to gravity diminishes the further you get from the centre of the earths mass. if you say double your distance from the earths centre, the force on you is quartered. the official equation for force between two masses is , . f = ((G * m1 * m2) / d^2) G = newtons gravitational constant m1 = mass 1 ( say earth) m2 = mass 2 ( say you) d = distance between centres of gravity
No. The circumference is the distance around a circle or equaltor wheras the radius is the distance from the centre of a sphere (the centre of the earch if you will) to the surface. the diameter is twice the distance of the radius and is the distance from the surface of a sphere, through the middle point across to the other surface.
It depends upon the mass of the object and distance from the centre of earth
The difference in gravitational acceleration depends on the distance from the centre of the earth , not the surface. The equation for the new rate of accelration calculated from the surface rate is: > a = k / ( ( d / r )2 ) > where: a = acceleration due to gravity at new position k = surface rate of acceleration ( use 9.82 (m/s)/s ) d = distance from earths centre to new position ( r + height of jump) ( 6376000 metres) r = surface radius ( use 6371000 metres ) > Even if you jump from 5,000 metres the rate of acceleration would be : > 9.8046 (m/s)/s , which is 99.84 % of the rate at the surface
Yes. In a perfect sphere the centre is an equal distance from any point from the surface.
From the centre of Albury to the centre of Wodonga is a distance of 5.53km.
Because the mountain is farther away from the gravitational centre of the Earth.
The surface of a sphere. It cannot be a sphere since points which are not on its surface will be nearer to the centre.
It is the distance from the centre to all points on the surface of a sphere with a radius of 1 foot.
At the centre of the Earth.
gravity follows an inverse squared law. at twice the distance it would be a quarter of G. 1/g2 = 1/2. so the distance would be the square root of 2 (or 1.4). 1.4 x earths radius of 6366 km would be 9003 km