If what you want to do is calculate the work, you need to multiply the force times the displacement.
The diagram showing the 5-newton force pointing east and the 10-newton force pointing south, where the two forces are perpendicular to each other, would best depict the situation.
The work done by the boy carrying the load on his head is zero, because the force applied is perpendicular to the displacement. Work is only done when the force and displacement are in the same direction.
The CGS unit of force is the dyne, while the SI unit of force is the newton. 1 newton is equal to 10^5 dynes.
If force increases by 5 times, then work will also increase by 5 times, assuming the displacement remains constant. This is because work is directly proportional to the force applied.
Work = Force*Displacement Therefore, work in this case is 5*15 = 75 J.
An object moves in a circle at constant speed. The work done by the centripetal force is zero because: 1. the displacement for each revolution is zero 2. the average force for each revolution is zero 3. there is no friction 4. the magnitude of the acceleration is zero 5. the centripetal force is perpendicular to the velocity
An object moves in a circle at constant speed. The work done by the centripetal force is zero because: 1. the displacement for each revolution is zero 2. the average force for each revolution is zero 3. there is no friction 4. the magnitude of the acceleration is zero 5. the centripetal force is perpendicular to the velocity
A 10 newton force is approximately 2.25 pounds-force, so the 5 pound force is greater.
The diagram showing the 5-newton force pointing east and the 10-newton force pointing south, where the two forces are perpendicular to each other, would best depict the situation.
The work done by the boy carrying the load on his head is zero, because the force applied is perpendicular to the displacement. Work is only done when the force and displacement are in the same direction.
5 N
In order for a force to produce a torque, either all of it, or a part of it (component) must act perpendicular to the moment arm. If, as in your case, all of the force is parallel to the moment arm then the force can not produce a torque. So the answer is; the torque is zero.
The CGS unit of force is the dyne, while the SI unit of force is the newton. 1 newton is equal to 10^5 dynes.
If force increases by 5 times, then work will also increase by 5 times, assuming the displacement remains constant. This is because work is directly proportional to the force applied.
Work = Force*Displacement Therefore, work in this case is 5*15 = 75 J.
the SI unit of force is the newton (symbol N), which is the force required to accelerate a one kilogram mass at a rate of one meter per second squared. It is equivalent to SI kgms-2. Any other unit of force can be derived from the formula F = ma and substituting whatever units are being for those variables.Some other units of force:1 dyne = 10-5 N1 kilogram - force (kgf) or kilopound (kp) = 9.80665 N = 1 metric slug1 lbf = 32.174 poundals = 1 slug1 kgf = 2.2046 lbf
You can't, unless you know both of their directions. -- If they're in the same direction, then the net force is 10N in that same direction. -- If they're in opposite directions, then the net force is zero, and the direction doesn't matter because there's no net force. -- Depending on their directions, those two forces can combine to produce a net force of anything between zero and 10 N, in any direction. So you need to know their directions in order to figure out what the net force is.