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If it took 5 seconds to lift the crate using a machine what was the power rating of the machine?
Wiki User
∙ 13y ago
We have no way of knowing what power the machine was rated for, but with the
information given in the question, we can calculate the power it delivered during
the crate-lift:
It was
(1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters)
watts.
Wiki User
∙ 13y ago
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From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
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