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Kinetic Energy = 1/2 (mass) (velocity)2
Measurement of mass is in error by 3%.
Measurement of velocity is in error by 4%.
If both are low, then KE is measured as
(True KE) x (.97) x (.96)2 = 0.894 TKE = 10.6% low.
If both are high, then KE is measured as
(True KE) x (1.03) x (1.04)2 = 1.114 TKE = 11.4% high.
If one is high and the other low, then the net error is in between these limits.
What else can I help you with?
If error in the measurement of momentum of a particle is 100 percent then the error in the measurement of kinetic energy is what?
p=mv %errror in p= %error in m+%error in v lowest value of m=0 hence %error in velocity=100% k.e=%error in mass=2*%error in velocity K.E=200% similarly K.Eminimun=100% total error in K.E = 100+200 =300 hence error in ke = 300%
How do you find the increase in kinetic energy if the percent increase in momentum is given?
Momentum = (mass) x (velocity), which is directly proportional to both mass and velocity.Since mass is constant, any change in momentum is the result of a change in velocity only.If the percent increase 'P' in momentum is given, velocity must have increased to (1 + 0.01P) of its original value.====================Kinetic energy = 1/2 (mass) x (velocity)2, which is directly proportional to mass and to the square of velocity.Since mass is constant, any change in kinetic energy is the result of a change in velocity only.If the velocity changes from its original value by a factor of (1 + 0.01P), the KE changes by a factor of (1 + 0.01P)2.The new KE is (1 + 0.01P)2 or [ 1 + 0.02P + 0.0001P2 ] times its original value.
What happens to velocity if you double kinetic energy?
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
What would be the new velocity of a body to make its kinetic energy double?
Momentum = mass * velocity = force * time Kinetic Energy = 1/2 * mass * velocity squared Since the mass of your object is not likely changing, it is the velocity which is changing. Therefore, your new velocity is 1.5 times your initial velocity. In the kinetic energy equation, velocity is squared. 1.5 squared = 2.25, and since nothing else is changing, your kinetic energy is now 2.25 times initial. This is an increase of 125%.
How much energy in joules does a regenerative brake produce when going from 60mph or 25 meter per second to zero?
You can use the formula for kinetic energy (1/2 x mass x velocity squared). However, I don't know how efficient those brakes are; that is, how much percent of the energy typically gets recovered.
If error in the measurement of momentum of a particle is 100 percent then the error in the measurement of kinetic energy is what?
p=mv %errror in p= %error in m+%error in v lowest value of m=0 hence %error in velocity=100% k.e=%error in mass=2*%error in velocity K.E=200% similarly K.Eminimun=100% total error in K.E = 100+200 =300 hence error in ke = 300%
When solutes and solvents are liquids then percent solution by is used?
Volume is used, because of the liquids velocity. (measurement)
How do you find the increase in kinetic energy if the percent increase in momentum is given?
Momentum = (mass) x (velocity), which is directly proportional to both mass and velocity.Since mass is constant, any change in momentum is the result of a change in velocity only.If the percent increase 'P' in momentum is given, velocity must have increased to (1 + 0.01P) of its original value.====================Kinetic energy = 1/2 (mass) x (velocity)2, which is directly proportional to mass and to the square of velocity.Since mass is constant, any change in kinetic energy is the result of a change in velocity only.If the velocity changes from its original value by a factor of (1 + 0.01P), the KE changes by a factor of (1 + 0.01P)2.The new KE is (1 + 0.01P)2 or [ 1 + 0.02P + 0.0001P2 ] times its original value.
How do accuracy and precision of measurement affect calculated values and percent error?
The more precise your instruments of measurement are, the less percentage of error you will have.
What is the percent error of the measurement 7cm?
what is the number supposed to be if you git 7 cm? Percent error is the percentage that you're incorrect by, so you need another measurement. to do it, you find the difference and then divide by the original so (7-x)/true value then multiply by 100 to get percentage.
What are percent errors?
A percentage error for a measurement is 100*(True Value - Measured Value)/True Value.
What is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?
.229/.225 = 1.0178 percent error = (1.0178 - 1) times 100 to get to percent = .0178 x 100 = 1.78%
What happens to velocity if you double kinetic energy?
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
What is percent by mass over volume?
Percent by mass over volume is a measurement that expresses the mass of a substance in a given volume as a percentage. It is calculated by dividing the mass of the substance by the volume of the solution and then multiplying by 100. This measurement is commonly used in chemistry to quantify the concentration of a solute in a solution.
What would be the new velocity of a body to make its kinetic energy double?
Momentum = mass * velocity = force * time Kinetic Energy = 1/2 * mass * velocity squared Since the mass of your object is not likely changing, it is the velocity which is changing. Therefore, your new velocity is 1.5 times your initial velocity. In the kinetic energy equation, velocity is squared. 1.5 squared = 2.25, and since nothing else is changing, your kinetic energy is now 2.25 times initial. This is an increase of 125%.
What is 125 percent into a percentage?
125 percent into a percentage = 125%
How much energy in joules does a regenerative brake produce when going from 60mph or 25 meter per second to zero?
You can use the formula for kinetic energy (1/2 x mass x velocity squared). However, I don't know how efficient those brakes are; that is, how much percent of the energy typically gets recovered.
