The energy E of a photon is E= h x f , where f is the frequency, and h is Planck's constant.
h=6.63e-34 [aka 6.63 x 10^-34] J s (Joule-seconds)
The frequency f of a photon is related to its wavelength by
f=speed of light/wavelength
Speed of light c=3e8 m/s.
From this you can calculate the energy of a 600nm photon, and then the number of those photons required to get 4e-17 Joules.
Your answer should be between 50 and 500, but you can do the math.
Wavelength, or alternatively its frequency.
The energy of a photon is directly proportional to the frequency. Since the frequency is inversely proportional to the wavelength, the energy, too, is inversely proportional to the wavelength.
Color wavelength and photon energy are inversely related. This means that as the wavelength of light decreases and the frequency increases, the energy of the photons also increases. Shorter wavelengths correspond to higher energy photons, such as in the case of ultraviolet light having higher energy than visible light.
When the wavelength of light is doubled, the energy of photons decreases by half.
Yes definitely. Reciprocal of wavelength is proportional to frequency as lambda = v /frequency. v - the speed of the wave. The frequency has to be greater than some minimum value known to be the threshold frequency. As frequency increases then kinetic energy of the photo electron also increases. If the frequency of the incident photon is less than the threshold and however higher the intensity, there is no chance of ejection of photo electron right from the surface of the substance. So no photo electric emission is possible.
Wavelength, or alternatively its frequency.
The energy of a photon is directly proportional to the frequency. Since the frequency is inversely proportional to the wavelength, the energy, too, is inversely proportional to the wavelength.
Color wavelength and photon energy are inversely related. This means that as the wavelength of light decreases and the frequency increases, the energy of the photons also increases. Shorter wavelengths correspond to higher energy photons, such as in the case of ultraviolet light having higher energy than visible light.
When the wavelength of light is doubled, the energy of photons decreases by half.
There is no longest wavelength for photons. It can be arbitrarily long.
High-energy photons correspond to short-wavelength light while low-energy photons correspond to long-wavelength light. In short, the answer is red. For short-wavelengths (high energy photons) it would appear blue.
The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.
Yes definitely. Reciprocal of wavelength is proportional to frequency as lambda = v /frequency. v - the speed of the wave. The frequency has to be greater than some minimum value known to be the threshold frequency. As frequency increases then kinetic energy of the photo electron also increases. If the frequency of the incident photon is less than the threshold and however higher the intensity, there is no chance of ejection of photo electron right from the surface of the substance. So no photo electric emission is possible.
The energy of the photons decreases as the wavelength increases
A photon's energy is determined by its frequency or wavelength, according to the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. In general, higher frequencies (or shorter wavelengths) correspond to photons with higher energy.
Same way it grows in sunlight. Photons of light at the right wavelength impact the pigment chlorophyll, excite and electron from the pigment which then enters photosystem II. Photons of the correct wave length are photons of the correct wavelength and the plant does not care what the source is of these photons.
To determine the number of photons corresponding to an energy of 3.96 × 10^-17 joules, you can use the equation (E = n \cdot h \cdot f), where (E) is the total energy, (n) is the number of photons, (h) is Planck's constant (approximately (6.626 \times 10^{-34} , \text{J s})), and (f) is the frequency of the photons. If you know the frequency or wavelength of the photons, you can calculate the number of photons (n) by rearranging the equation to (n = \frac{E}{h \cdot f}). Without knowing the frequency, you cannot calculate the exact number of photons.