0
If the masses remain the same but the distance of separation is decreased to one half the original distance what happens to the gfravitational force?
The gravitational force between the masses would increase by a factor of 4. This is because the gravitational force is inversely proportional to the square of the distance between the masses, so reducing the distance by half would increase the force by a factor of (1/0.5)^2 = 4.
What else can I help you with?
What happens to the force between the charges when the separation distance is tripled?
The force between charges decreases to (1/9) of the original force when the separation distance is tripled according to Coulomb's Law. This is because force is inversely proportional to the square of the separation distance.
Find the change in the force of gravity between two planets when the distance between them is decreased by a factor of five?
it will increase by a factor of 25.since F= G . M m/ d2 thus when the distance decrease by a factor of five i.e to fifth of the original distance the grvitational force will increase by 25 (1/5) 2 .
How does the distance between two-interacting bodies affect the force of gravity?
Assuming the (toatal) mass doesnt alter Treat original distance as 1, the original force as 1 and new distance (d) as direct comparison to the old, then the force of gravity is: 1 / d2 Example: If the new distance is three times the original, then: f = 1 / 32 f = 1 / 9 = 0.111 times the original force. Example: If the new distance is half the original distance, then: f = 1 / 0.52 f = 1 / 0.25 = 4 times the the original force.
What happened to the size of the real image as the object was slowly moved toward the lens from its original position beyond 2 focal lengths?
As the object was moved closer to the lens from beyond 2 focal lengths, the real image became larger in size. This is because the image distance decreased while the object distance increased, leading to a magnified real image being formed by the lens.
Two charged dust particles exert a force of 5.2 10-2 N on each other What will be the force if they are moved so they are only one seventh as far apart?
The force between two charged particles is given by Coulomb's Law, F=kq1q2/r^2, where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between them. If the distance is decreased to 1/7 of the original distance, the force will increase by a factor of (original distance/new distance)^2, which is (1/7)^2 = 1/49. Therefore, the new force will be 49 times greater, so the force will be 5.2 * 49 = 254.8 x 10^-2 N.
What happens to the force between the charges when the separation distance is tripled?
The force between charges decreases to (1/9) of the original force when the separation distance is tripled according to Coulomb's Law. This is because force is inversely proportional to the square of the separation distance.
Charged paritcles when they are brought to half their original distance of separation?
The force between them increases to 4 times what it was before they moved.
How do you find the percentage of a decreased number?
% decrease = |original value - new value|/original value * 100%
If 4 is decreased to 1 the decrease is what percent of the original number?
It is 75%.
A number is decreased by 65 percent to 203 what is the original amount?
580
What is the area of a square decreased from one hundred square meters to eighty one square meters find the percent decreased in area?
81 is 81% of 100. Anything that decreased from 100 to 81 decreased by 19 percent of its original value.
Find the change in the force of gravity between two planets when the distance between them is decreased by a factor of five?
it will increase by a factor of 25.since F= G . M m/ d2 thus when the distance decrease by a factor of five i.e to fifth of the original distance the grvitational force will increase by 25 (1/5) 2 .
What is the volume of a cube 80cm long if it is decreased by 10 percent?
This depends on what you mean by "it". The volume of the original cube is V = (80 cm)³ = 512,000 cm³. If the volume is decreased by 10%, then multiply the volume of the original cube by 0.9 to get 406,800 cm³. Otherwise, if the length of the cube is decreased by 10%, then: V = (80 cm * 0.9)³ ≈ 373248 cm³
What was the original distance of the Kentucky Derby racetrack?
A distance of 1-1/2 miles was the original length of the Kentucky Derby racetrack. That was the distance for the first 20 years, 1875-1895. As of 1896, the distance was shortened to 1-1/4 miles.
How does the force of gravity between two bodies change when the distance between them tripled?
The gravitational pull of an object in relation to its distance from another object is an inverse square law. When the distance between two objects is doubled, their pulled on each other is quartered. G ∝ 1/r2 where G is the gravitational pull and r is the separation.
What was th original amount when decreased by 15 and it is now 189?
It was 204 because 204 minus 15 equals 189
Is a patteren in which a minority person rejects the majority cultures ways and tries to maintain the original culture identity?
separation
