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The velocity of a car changes from 15ms south to 5ms south in 2 seconds what is the acceleration of the car?
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Substituting the values: acceleration = (5 m/s - 15 m/s) / 2 s = -5 m/s^2. Therefore, the acceleration of the car is -5 m/s^2, indicating that it is decelerating.
You and your bike have a combined mass of 80kg. How much braking force has to be applied to slow you from a velocity of 5ms to a complete stop in 2s?
To calculate the braking force, we need to determine the deceleration first. Using the formula: final velocity = initial velocity + (acceleration * time), we find that the deceleration is 2.5 m/s^2. Then, using the formula: force = mass * acceleration, we get a braking force of 200 N.
What is momentum of a 3kg object moving at 5ms?
The momentum of an object is calculated as the product of its mass and velocity. So, the momentum of a 3kg object moving at 5m/s would be 15 kg*m/s.
If a 2 kg mass is acted upon by a force of 10 newton what is the acceleration?
F = ma. Thus, acceleration is the force divided by the mass. Here, 10/2 = 5ms-2.
A 10kg cart is moving at 5ms collides with a 5kg cart at rest and Causes it move 10ms What principle explain the result?
The principle of conservation of momentum explains this result. The total momentum of the system before the collision is equal to the total momentum after the collision. In this case, the momentum gained by the 5kg cart moving at 10 m/s is equal to the momentum lost by the 10kg cart, resulting in a balanced conservation of momentum.
The velocity of a car changes from 15ms south to 5ms south in 2 seconds what is the acceleration of the car?
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Substituting the values: acceleration = (5 m/s - 15 m/s) / 2 s = -5 m/s^2. Therefore, the acceleration of the car is -5 m/s^2, indicating that it is decelerating.
You and your bike have a combined mass of 80kg. How much braking force has to be applied to slow you from a velocity of 5ms to a complete stop in 2s?
To calculate the braking force, we need to determine the deceleration first. Using the formula: final velocity = initial velocity + (acceleration * time), we find that the deceleration is 2.5 m/s^2. Then, using the formula: force = mass * acceleration, we get a braking force of 200 N.
If a runner covers the last straight stretch of a race in 4s. during that time he speeds up from 5ms to 9ms. What is the runners acceleration in this part of the race?
4m/s Acceleration = velocity change / time = (9m/s - 5m/s) / 4 sec A = (9-5) / 4 = 1 m/s2.
A skydiver slows down from 65ms to 5ms by opening the parchute if this takes 0.75 seconds what is the skydiver's accerlation?
66.7 m/s2
What is momentum of a 3kg object moving at 5ms?
The momentum of an object is calculated as the product of its mass and velocity. So, the momentum of a 3kg object moving at 5m/s would be 15 kg*m/s.
How much force is needed to accelerate a 70 kg runner at 5ms 2?
Force=mass*acceleration -> (70 kg)*(5m/s^2)=350 kg m/s^2 OR 350 N (newtons)
Which of the 5Ms is affected by the actions of the other 4Ms?
Mission
What do you mean by 5ms-2?
While typing there is no provision to raise -2 as the power of s ie s-2 So it has been just typed as ms-2. m s-2 read as metre per second sqare. This is the unit for acceleration. So 5 ms-2 is the acceleration on a moving body.
What is absolute volocity?
Use Pythagoras' Theorem to find its value. For example, if it was moving at 3ms-1 in the x direction and 4ms-1 in the y direction, its absolute velocity would be the square root of (9+16), 5ms-1.
If a 2 kg mass is acted upon by a force of 10 newton what is the acceleration?
F = ma. Thus, acceleration is the force divided by the mass. Here, 10/2 = 5ms-2.
Which LCD monitor is faster 2ms or 5ms?
2ms lower faster
A 10kg cart is moving at 5ms collides with a 5kg cart at rest and Causes it move 10ms What principle explain the result?
The principle of conservation of momentum explains this result. The total momentum of the system before the collision is equal to the total momentum after the collision. In this case, the momentum gained by the 5kg cart moving at 10 m/s is equal to the momentum lost by the 10kg cart, resulting in a balanced conservation of momentum.
