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Well...you can't. Not a load with an exact 1 watt power rating. But if you can live with a 2-watt power rating (in a circuit that would be yes--it's called derating and you do it for added life, or because you've already got the parts) you'd connect two resistors in series and set that aside, connect two more resistors in series, then connect the two series networks in parallel. Each series network is rated at 2 kilohms; paralleling the two networks brings you back down to 1 kilohm.

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Q: If you are only given 1 kilo ohms resistors with 0.5 watt power rating how can you construct a resistive load of 1 kilo ohms with 1 watt power rating?
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