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∙ 14y agoIf a bullet was fired towards the groung it would be accelerated at a rate of 9.9 meters per second2 due to the force of gravity. The time gravity would have to act and the velocit of the bullet is so great that the extra velocity would be insignificant.
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∙ 8y agoWiki User
∙ 14y agoit will slow down and hit you in the head.
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∙ 13y agoWithout air resistance, they hit the ground at the same time.
Yes, bullets can ricochet from striking frozen ground, from water or any hard object.
1). Your speed in the forward direction should increase somewhat, since the recoil of the shot adds to your momentum. 2). The bullet you fire in the reverse direction leaves the muzzle with full muzzle velocity and momentum in the reverse direction ... in your frame of reference. Viewed by an observer in the stationary frame of reference ... the one in which you are moving at the speed of a bullet ... the one you fire just dribbles out of the muzzle and falls straight to the ground.
Assuming no affects from air and a smooth geography, both bullets would fall at the same rate of 9.81 m/s^2 toward earth, and hit the ground simultaneously. You have to look at the bullet's velocity as having a horizontal and vertical velocity vectors. The vertical velocity vector is independent from that of the horizontal. The horizontal vector would be the speed at which the bullet is fired, and the vertical vector is the speed at which the bullet falls due to gravity.
it all depends on the speed that the bullet is shot at. other contributing factors include the angle of the shot and the distance from the ground that the bullet is shot at. sadly, the x-factor of this question is that the ground determines how far it will ricochet. if the ground is water, it will not ricochet.
Bullets have no explosives. You may be thinking of a cartridge, which is a case, powder, primer, and bullet. It is very unlikely that the cartridge will do much of anything, but if the primer is struck hard enough, it can make a loud bang, but is unlikely to hurt anyone.
Yes, bullets can ricochet from striking frozen ground, from water or any hard object.
1). Your speed in the forward direction should increase somewhat, since the recoil of the shot adds to your momentum. 2). The bullet you fire in the reverse direction leaves the muzzle with full muzzle velocity and momentum in the reverse direction ... in your frame of reference. Viewed by an observer in the stationary frame of reference ... the one in which you are moving at the speed of a bullet ... the one you fire just dribbles out of the muzzle and falls straight to the ground.
no! all bullets fall. A bullet dropped from the edge of a table at the same time a bullet at the same table height leaves a barrel hits the ground at the same time.
Assuming no affects from air and a smooth geography, both bullets would fall at the same rate of 9.81 m/s^2 toward earth, and hit the ground simultaneously. You have to look at the bullet's velocity as having a horizontal and vertical velocity vectors. The vertical velocity vector is independent from that of the horizontal. The horizontal vector would be the speed at which the bullet is fired, and the vertical vector is the speed at which the bullet falls due to gravity.
Depends on the bullets, the "aim," the velocities, etcetera. Assuming two exact same bullets, from same load (powder charge, primer type, from same rifle/handgun, the mass/velocities would cancel out, and the bullets would expend each other's energy and the two would fall harmlessly to the ground at the point of impact. In reality, the same cartridges, even if fired from the same gun, would never have the bullets with the exact same velocity and weight, so the two bullets would continue in the direction of the faster bullet. More complications? the bullet type (pure lead, hard lead (alloyed to increase hardness), jacketed, and (of course) frangible bullets would all effect the outcome, but the simple answer is "conservation of mass/velocity/energy" (I'm assuming you mean two VERY STUPID or Very Drunk people shooting at each other, in which case the "Darwin Award" should go to these two fools). [By "bullet", I mean the projectile, as compared to the "cartridge," which would include the brass case, the primer, the powder, and the bullet]
If a gun was parallel with the earth and was fired and at that very instant someone standing by the barrel dropped a bullet from beside the barrel, both bullets would hit the ground at the same time. Bullets start falling the instant they leave the end of the gun barrel. That is why hunters hold their rifles at an upward angle. It looks like the bullet will shoot up into the sky. The bullet will follow a curved path toward its target.
In theory, if a bullet dropped vertically at the same instant that a bullet is fired horizontally from a gun at the same height, they should both hit the ground at the same time.This example is used to emphasize that that horizontal motion and vertical motion may be analysed separately since they occur independently of each other.This is one of those things that works better in theory than in practice.There is a caveat that is important if you consider doing this in the real world. The process is not happening in a vacuum. The aerodynamics of the bullet fired at high speed is tremendously important. In early gun design, this was not understood and bullets fired from guns were very inaccurate and went up or down or right or left in unpredictable ways. Modern guns stabilize the trajectory by putting a spin on the bullet. The result makes the bullet act like a gyroscope and then to remain pointed forward when it encounters small anomalies in the air and wind. So, the moving bullet is subjected to vertical forces and can not be expected to drop at the same rate as a bullet with no horizontal motion.The principle of independent horizontal and vertical motion works better when illustrated by throwing and dropping heavy rocks. The principle is entirely correct, but there are more vertical forces involved than gravity with the bullets.
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
If you don't take into consideration the curvature of the earth, both should hit the ground at the same time. Both bullets would be affected by gravity at the same rate, (32 ft/sec/sec) even though the horozontal vector is greater, the vertical is identical. IF you have a bullet that is going fast enough to travel far enough to be affected by earths curvature, the faster bullet would hit the ground later.
No. The horizontal distance depends on how close the the ground the gun is. From the firing position, a bullet dropped to the ground will strike the ground in the same time as a bullet shot horizontally forward.
it all depends on the speed that the bullet is shot at. other contributing factors include the angle of the shot and the distance from the ground that the bullet is shot at. sadly, the x-factor of this question is that the ground determines how far it will ricochet. if the ground is water, it will not ricochet.
Falling three feetThis is a common question in elementary physics and the wrong answer (that the bullets will land at the same time) is given quite frequently. Though some would argue that factoring in lift due to exceeding terminal velocity is excessive and needlessly complicates things to make a point that changes the answer only slightly, the truth of the matter is that the fired bullet will take almost twice as long to land. Although you didn't state it explicitly in your question, we will assume the bullet fired from the rifle starts out three feet off the ground, not at shoulder height.Assuming that, the bullets will strike the ground at nearly the same time!! For many people that is a counter-intuitive answer.Orthogonal forces -- that is, forces at right angles to each other -- have no effect on each other. When a bullet is fired from a gun, the force due to gravity works at right angles to the bullet's horizontal motion. The bullet's horizontal motion and any forces acting on the bullet in the horizontal direction have no effect on the motion of, or the forces acting on, the bullet in the vertical direction.When the bullet leaves the end of the muzzle of the gun, gravitational forces will start to act on the bullet immediately. The bullet will accelerate toward the ground at 9.8 meters per second squared (32.2 feet per second squared), just like any object that is dropped and falling freely.At this point you might think they would strike the ground simultaneously. However, drag forces caused by the bullet exceeding terminal velocity would cause a lift. Similar to the principle upon which plane flight is based. This would cause the fired bullet to stay airborne slightly longer than the dropped bullet.The dropped bullet will strike the ground in about 432 milliseconds (0.432 second).The fired bullet will land shortly after.(Except the bullet would go far beyond an empty football field, unless it hit a wall at the end of it or something...)