The ball will reach zero speed at the peak of its trajectory after approximately 2 seconds. This is because the acceleration due to gravity will gradually slow down the ball until it stops momentarily before falling back down.
To find the time taken for an object to reach the peak of its path when thrown straight upward with a velocity of 50 m/s, you can use the formula: time = velocity / acceleration. Since the object is moving against gravity, the acceleration will be the acceleration due to gravity (-9.81 m/s^2). Therefore, the time taken to reach the peak will be 50 m/s / 9.81 m/s^2 = approximately 5.1 seconds.
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
(Once again, as we always do with problems like this one, we have to ignorethe effects of air resistance. Sorry. It's just too complicated if we don't.)The acceleration of gravity is 9.8 meters per second2. That means that anyobject that's not propelled or constrained gains 9.8 m/s of downward speedevery second.The arrow starts with 196 m/s of upward speed. It loses 9.8 m/s of that speedevery second. It'll run out of upward speed and start moving downward after196/9.8 = 20 seconds .
The minimum velocity of the missile would depend on the time it takes for the missile to reach the target. If the missile travels 100 meters in 1 second, then the minimum velocity would be 100 m/s.
In a vacuum it would fall back to the same height at the same speed, 150m/s. It would then gain another minuscule fraction of speed as it fell from bat-height down to the ground. In the real world, a falling baseball will reach a maximum speed of around 42 meters per second because the air resistance slows it down. This is called Terminal Velocity.
Initial upward speed = 7.61 m/sFinal upward speed (at the point of maximum height) = 0Time to reach maximum height = (7.61) / (9.8) = 0.77653 secondAverage speed during that time = 1/2 ( 7.61 + 0) = 3.805 m/sHeight = 3.805 x 0.77653 = 2.9547 meters (rounded) = about 9.7 feetDoesn't seem like much of a height for a strong toss; but the math looks OK.
To find the time taken for an object to reach the peak of its path when thrown straight upward with a velocity of 50 m/s, you can use the formula: time = velocity / acceleration. Since the object is moving against gravity, the acceleration will be the acceleration due to gravity (-9.81 m/s^2). Therefore, the time taken to reach the peak will be 50 m/s / 9.81 m/s^2 = approximately 5.1 seconds.
If you could travel in a straight line from the sun to the earth at 1,000 meters per second,(2,237 miles per hour), the trip would take 4years271days. (rounded)
The AA-12 shotgun shell can reach up to 175 meters per second.
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
Light travels at about 300,000 metres per second. The time taken for that light to reach us would depend on the stars distance.
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"ms" in this case is short for "meters per second". It means that sound advances that many meters every second.
(Once again, as we always do with problems like this one, we have to ignorethe effects of air resistance. Sorry. It's just too complicated if we don't.)The acceleration of gravity is 9.8 meters per second2. That means that anyobject that's not propelled or constrained gains 9.8 m/s of downward speedevery second.The arrow starts with 196 m/s of upward speed. It loses 9.8 m/s of that speedevery second. It'll run out of upward speed and start moving downward after196/9.8 = 20 seconds .
Answer is .00606 of a second.
Speed=15t + 10 The 15t accounts for acceleration, while the initial velocity of 10 is accounted for by +10. As such, the amount of time (t) for the car to reach 20m/s is 2/3s.
If you're talking about an object falling straight downward, that object being affected by a gravitational pull of 9.81m/sec, ignoring air resistance, it would take the object around 5 seconds to reach 49m/sec.