600 m/s2
( About 61 G's ! )
The acceleration of the projectile can be calculated using the formula: acceleration = (final velocity - initial velocity) / time Plugging in the values: acceleration = (300 m/s - 0 m/s) / 0.5 s acceleration = 600 m/s^2 Therefore, the acceleration of the projectile is 600 meters per second squared.
The acceleration of a projectile fired vertically down is equal to the acceleration due to gravity, which is -9.81 m/s^2. The negative sign indicates that the acceleration is in the downward direction.
Assuming the projectile is subject only to gravity and air resistance is negligible, a projectile will fall approximately 4.9 meters (16 feet) in one second. This is because the acceleration due to gravity is 9.8 m/s^2, and in one second, the projectile will be traveling at this speed.
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
The plane's velocity at 10 seconds will be 150 meters per second or 335.54 mph
The acceleration of the projectile can be calculated using the formula: acceleration = (final velocity - initial velocity) / time Plugging in the values: acceleration = (300 m/s - 0 m/s) / 0.5 s acceleration = 600 m/s^2 Therefore, the acceleration of the projectile is 600 meters per second squared.
Acceleration at the point of zero vertical velocity will be equivalent to gravitational acceleration on that body. On Earth, for example, this is around 9.8 meters per second per second (9.8m/s2).
The acceleration of a projectile fired vertically down is equal to the acceleration due to gravity, which is -9.81 m/s^2. The negative sign indicates that the acceleration is in the downward direction.
The acceleration of the body is 3 m/s²
The sprinter's acceleration is 2 meters per second squared.
acceleration = change in velocity divided by timeaccel = (9-3)/3 = 6/3 = 2 meters per second per second
Assuming the projectile is subject only to gravity and air resistance is negligible, a projectile will fall approximately 4.9 meters (16 feet) in one second. This is because the acceleration due to gravity is 9.8 m/s^2, and in one second, the projectile will be traveling at this speed.
"470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed.
Because if speed is measured in meters per second (m/s) and time is measured in seconds, the SI unit of acceleration is meters per second per second (m/s2). ^_^
Acceleration = (change in speed) divided by (time for the change)Acceleration = (96 - 32) / 8 = 64/8 = 8 meters per second2
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
-2.33 metres per second squared