Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.
Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.
Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.
Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.
3.0 seconds after being dropped, a freely falling object, unaffected by air resistance,
near the surface of the earth, is falling at the rate of 29.4 meters (96.5 feet) per second.
Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.
You can use the formula for constant acceleration for problems like this one.
29.4
29.4 m/s
On object falling under the force of gravity (9.8 m/s2) would, in a vacuum, fall a distance of 706 metres in 12 seconds. In a non-vacuum, i.e. air, the object would fall less distance in the same time due to drag.xt = 0.5 (9.8) t2
500 metres per second.
The answer depends on:where it is falling (if on a space ship, the answer may be 0)the extent to which air resistance affects the fall.
29.4
194fps
29.4 m/s
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
Ignoring air resistance, it would be 706 meters .
Ignoring air resistance, that would be about 145 feet.
On object falling under the force of gravity (9.8 m/s2) would, in a vacuum, fall a distance of 706 metres in 12 seconds. In a non-vacuum, i.e. air, the object would fall less distance in the same time due to drag.xt = 0.5 (9.8) t2
Ignoring air resistance, it would have taken 7.3 seconds, approx.
500 metres per second.
If you're talking about an object falling straight downward, that object being affected by a gravitational pull of 9.81m/sec, ignoring air resistance, it would take the object around 5 seconds to reach 49m/sec.
Perhaps you meant speed or velocity, because the vertical acceleration is constant throughout the bomb's decent, ignoring the effects of air resistance. The acceleration due to gravity is 9.8 m/s2 for all values of t.
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.