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Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.

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9y ago
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14y ago

Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.

Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.

Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.

Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.

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12y ago

3.0 seconds after being dropped, a freely falling object, unaffected by air resistance,

near the surface of the earth, is falling at the rate of 29.4 meters (96.5 feet) per second.

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14y ago

Since acceleration due to gravity is 9.82 meters per second square = 9.82 (meters/second)/second, in 3 seconds you get a speed of 3 x 9.82 meters per second.

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9y ago

You can use the formula for constant acceleration for problems like this one.

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Q: Ignoring the effects of air resistance what is the speed in of the object after falling 3 seconds?
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