The answer depends on:
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
An object in free fall will fall approximately 64 feet in 2 seconds.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
Neither. When a rubber ball gets hot, the rubber begins to lose its elasticity. It doesn't bounce as high. When a rubber ball gets really cold, it starts to behave rather like a rock. It hardly bounces at all The temperature of highest bounce depends on exactly what the ball is made of, but it is probably not all that far from room temperature.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
An object in free fall will fall approximately 64 feet in 2 seconds.
Depends on the speed the ball travels.
1,100 to 1,300 feet.
If the ball is lighter than the hard ball, then it is because a heavier ball has more force when moving at the same speed as a lighter ball. If they weigh the same, then it is because in some instances, with certain materials, a hard ball with a lot of "ping" to it will bounce further than a rubber ball, due to motive energy being converted to heat in the polymers of the rubber ball, thus decreasing the total motive energy.
Yes it does. If the rubber is to cold the molecules in the rubber will not deflect "spring" allowing. If the rubber is to hot then those same molecules are to far apart to interact with each other in an optimal way.
It has been known since the 16th century that the mass of an object is irrelevant to how far it will fall. The main factor influencing the rate of fall is the shape of the object and, therefore, the air resistance (or buoyancy).
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
It depends.If the object is a helium balloon, it will not fall on the surface of the earth. If it is a feather, it will fall much more slowly than a ball bearing. A ball bearing will fall much facter on the surface of the earth than it will on the moon.But, if you assume thatthe object is falling under the force of earth's gravity,It is a compact and massive object so that air resistance may be ignored, thens = 0.5*9.8*372 = 6708.1 metres.
It all depends on the weight of the ball but if a tennis ball was thrown it would travel 2 1/2M in 2 seconds but cannot be calculated like this because the further the ball falls the more speed it gains. However there is a trick to this question because the 2nd second is only one second itself. making the answer 1M and 10CM !
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
the fourth hit will be approx 1.4 metres