An object in free fall will fall approximately 64 feet in 2 seconds.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
Assuming the object starts from rest, the distance an object falls in 0.25 seconds can be calculated using the equation ( d = \frac{1}{2}gt^2 ), where (d) is the distance, (g) is the acceleration due to gravity (9.8 m/s²), and (t) is the time. Substituting the values, the object would fall approximately 0.31 meters in 0.25 seconds.
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
The object will move a total distance of 80 meters, which is calculated by multiplying the speed (10 m/s) by the time (8 seconds).
Assuming the object is in free fall near Earth's surface, it will fall approximately 343.3 meters (1126 feet) in 7 seconds. This calculation is based on the formula for free fall distance: d = 1/2 * g * t^2, where d is the distance fallen, g is the acceleration due to gravity, and t is the time in seconds.
1,100 to 1,300 feet.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
Because this is a free fall questions, the equation d=1/2gt² can be used. Gravity is a given, 9.8 m/s² and the time is your 15 seconds of free fall. d=1/2(9.8m/s²)(15s)²= 1,102.5m. To find feet multiply 3.28084 to answer because that is how many feet are in a meter.
It has been known since the 16th century that the mass of an object is irrelevant to how far it will fall. The main factor influencing the rate of fall is the shape of the object and, therefore, the air resistance (or buoyancy).
122.5 meters (402.5 feet)
Assuming the object starts from rest, the distance an object falls in 0.25 seconds can be calculated using the equation ( d = \frac{1}{2}gt^2 ), where (d) is the distance, (g) is the acceleration due to gravity (9.8 m/s²), and (t) is the time. Substituting the values, the object would fall approximately 0.31 meters in 0.25 seconds.
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
Assuming free fall in a vacuum, an object will fall approximately 64 meters (210 feet) in 4 seconds, as acceleration due to gravity is 9.81 m/s^2. However, in reality, air resistance would slow down the fall, so the distance would be slightly less. It's important to consider factors such as air resistance, initial velocity, and gravitational acceleration when calculating the distance fallen in a specific timeframe.
An object dropped from near the Earth's surface will fall approximately 4.9 meters (16 feet) in the first second due to the acceleration of gravity. This distance is calculated using the formula s = 0.5 * g * t^2, where s is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time in seconds.
To determine how far a pebble falls in ten seconds, we can use the formula for the distance of free fall, which is (d = \frac{1}{2}gt^2), where (g) is the acceleration due to gravity (approximately 32 feet per second squared) and (t) is the time in seconds. Plugging in the values, we get (d = \frac{1}{2} \times 32 \times (10^2) = 1600) feet. Therefore, a pebble falls approximately 1,600 feet in ten seconds.