A. 5 m/s
To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
The total momentum before the collision is 10,000 kg m/s (1000 kg * 10 m/s) in the direction of Car 2's initial velocity. Since the system is isolated, momentum is conserved. After the collision, the total momentum is still 10,000 kg m/s, but now shared between the two cars.
10 m/s
By conservation of momentum in an isolated system, the total momentum before the collision is equal to the total momentum after the collision. You can calculate this using the formula for conservation of momentum, which states that the initial momentum of car 2 is equal to the combined momentum of both cars after the collision. With this information, you can determine the common final speed of the two cars after the collision.
They move with a speed of 3 ms^-1.
They move with a speed of 3 ms^-1.
5 m/s APPEX ;)
10,000
7,500 Kg-m/s
10,000 kg-m/s
10,000 kg-m/s
10,000 kg-m/s
Law of Conservation of Momentum: The total momentum after the collision is equal to the total momentum before the collission.
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.
The "C" stands for "Collider" For something to collide there has to be a second something moving in a different direction to collide with. The contents of the two beams moving in opposite directions collide.