3 ATM at 20 meters.
To experience a pressure of 2 ATM, you would need to dive to a depth of 20 meters (2 ATM = 1 ATM (surface) + 1 ATM (pressure at 10 meters depth)). At a depth of 100 meters, the pressure would be approximately 11 ATM (1 ATM at surface + 1 ATM for every 10 meters).
The pressure at 20 meters below sea level is approximately 3 atmospheres, which is equivalent to about 2,942 millibars or 294.2 kPa. This pressure is due to the weight of the water above exerting force on the area at that depth.
20 BAR is equivalent to 200 meters (or 660 feet) of water depth. It represents the pressure that can be sustained at that depth underwater.
One Bar is 10.2 Meters of fresh water or 9.0 meters of saltwater. it is 204 meters for fresh water. and 180 meters in salt water. :-)
Water pressure is caused by the weight of the water that is above it. At deeper levels there is more water above you. So there is more mass pressing on the water you are in. Pressure does not depend on the width, only on the depth. It is the same in a large basin as it is in an equally high pipe. On the surface there is also atmospheric pressure, because the atmosphere (the air) also has mass. This pressure must be added to the water pressure. It is roughly the same as 10 meters of water pressure. So, at 10 meters under water you have twice as much pressure than at the surface, at 20 meters three times as much, and so on. Seawater is heavier than freshwater, because there is salt in it. So the water pressure for every meter of depth in the sea is slightly higher than it is in a lake.
To experience a pressure of 2 ATM, you would need to dive to a depth of 20 meters (2 ATM = 1 ATM (surface) + 1 ATM (pressure at 10 meters depth)). At a depth of 100 meters, the pressure would be approximately 11 ATM (1 ATM at surface + 1 ATM for every 10 meters).
The absolute pressure at 20 meters underwater can be calculated using the formula: ( P = P_{atm} + \rho g h ), where ( P_{atm} ) is the atmospheric pressure at sea level (approximately 101.3 kPa), ( \rho ) is the density of water (around 1000 kg/m³), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( h ) is the depth in meters. At 20 meters, the pressure due to the water column is about 196.2 kPa (1000 kg/m³ × 9.81 m/s² × 20 m). Adding atmospheric pressure, the total absolute pressure is approximately 297.5 kPa.
The partial pressure of oxygen can be calculated by multiplying the percentage of oxygen in the air by the total pressure. In this case, 20 percent of 6.3 ATM is 1.26 ATM. Therefore, the scuba diver is breathing oxygen at a partial pressure of 1.26 ATM.
The solubility of oxygen gas in water at 20°C is approximately 0.0289 mmol/L under 1 atm pressure.
The pressure at 20 meters below sea level is approximately 3 atmospheres, which is equivalent to about 2,942 millibars or 294.2 kPa. This pressure is due to the weight of the water above exerting force on the area at that depth.
At 20 degrees Celsius and 25 ATM pressure, carbon dioxide would be in a supercritical state, exhibiting properties of both a gas and a liquid.
You question is not clear, but I think you mean to ask how deep in water is a pressure of 20 Bars. A bar is one atmosphere pressure which is about 10 meters of water depth. Since water is incompressible, the relationship is linear. 20 Bars is 200 meters depth.
At a pressure of 1,013 bar and a temperature of 0C: 4,61 vol. chlorine in 1 vol. water.
Water has a weight. The more you stack up the more it weighs. There fore if you stack up 10 meters or 20 meters it makes a big difference.
20 BAR is equivalent to 200 meters (or 660 feet) of water depth. It represents the pressure that can be sustained at that depth underwater.
You can't convert meters to bars, or bars to meters. The two are utterly incompatible. Meters is a unit of length, bars is a unit of pressure. if you mean depth of water then 20 bar = 200 metres (close)
In these conditions carbon dioxide is a gas.