Yes, that looks correct, if you use only the magnitudes of the vectors, i.e. the "dot" product.
Force x speed = force x (distance / time) = (force x distance) / time = work (energy) / time = power.
No. Net force is measured in Newtons, while velocity is measured in m/s. A net force can change an object's velocity.
Force is the rate of change of momentum (which is the product of mass and velocity) whereas power is the rate of work done (product of force and displacement) In fact, it can be shown that power = force x velocity
An object's force (in Newtons) is the product of its velocity and acceleration: F = m x a
Tangential velocity is equal to (mass x velocity^2)/radial distance
Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
power = force x velocity velocity = distance/time = 68 x 11/3 = 2.2/0.6 = 249.3 Watts = 11/3
Force is the rate of change of momentum (which is the product of mass and velocity) whereas power is the rate of work done (product of force and displacement) In fact, it can be shown that power = force x velocity
Assuming you're talking electronics: Power = Voltage x Current. Or, W = V x I. Also, in physics: Power = Work/Time. Also, Power = Force x Velocity
impulse (force x time) is equal to momentum (mass x velocity); Ft=mv
An object's force (in Newtons) is the product of its velocity and acceleration: F = m x a
Energy transferred (or work done, E) is equal to force (F) multiplied by the distance moved in the force's direction, x. E = Fx Rearranging F = E/x And substituting F = power x time F = 77000 x 35/16 = 168437.5 Newtons, which is the weight of the load. This model assumes constant velocity.
Tangential velocity is equal to (mass x velocity^2)/radial distance
It's equal to the change in velocity (final velocity - initial velocity).
Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
x to the power a divided by x to the power b is x to the power (a - b) When a and b are equal then this is x to the power a divided by x to the power a, ie 1. x to the power (a - a) = x to the power zero. Things which are equal to the same thing are equal to each other, so 1 = x to the power zero.
You would need to know how fast it is going to determine the force that the 50 hp motor is pushing the boat. Energy = Force X Distance. Divide both sides by time: Energy/time = Force X Distance/Time = Force X Speed, and Energy/Time = Power, so Power = Force X Speed, and Force would equal Power/Speed.
Velocity = (velocity when time=0) + (Force x time)/(mass) ===> F = MA A = F/M V = V0 + A T
power = force x velocity velocity = distance/time = 68 x 11/3 = 2.2/0.6 = 249.3 Watts = 11/3