No, the horizontal component of velocity remains constant for an object in projectile motion as long as no external forces act horizontally on the object. In the case of a ball thrown upward, the horizontal component of velocity remains unchanged unless affected by air resistance or other external forces.
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
When a body is thrown horizontally with uniform speed, there is no change in the horizontal velocity, so the horizontal component of acceleration is zero. The only acceleration acting on the body is due to gravity in the vertical direction.
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
When a body is thrown horizontally with uniform speed, there is no change in the horizontal velocity, so the horizontal component of acceleration is zero. The only acceleration acting on the body is due to gravity in the vertical direction.
The horizontal velocity of a thrown object is independent of its vertical velocity. This means that an object can be thrown horizontally with a certain speed, while also being affected by gravity vertically. The two motions are separate and do not directly influence each other.
If there's no influence from air resistance, then the path of a "projectile" is a parabola. That's what you get when one component of velocity is constant and its other (orthogonal) component is accelerated.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
The motion of an object thrown at an angle is a combination of both horizontal and vertical motion. The horizontal motion is constant and is controlled by the initial velocity in the x-direction. The vertical motion is influenced by gravity, causing the object to follow a curved path.
9.8
Your question is incomplete. It sounds like you are asking how the object falls. Aside from air resistance, the only force acting on it is the vertical component of gravity. Therefore, the object will fly a distance x = v (2d/g)1/2 where v is the horizontal velocity, d is the distance from the ground, and g is the acceleration of gravity.