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What else can I help you with?
Which lens does not form a real image?
concave lens does not form a rel image and convex MIRROR does not form a real image
Why can you not form a real image on the screen using a single diverging lens?
A single diverging lens always produces a virtual image. This is because the light rays that pass through the lens appear to diverge as they are traced back on the same side as the object, making it impossible for them to converge to form a real image on a screen.
Can not form virtual image?
A virtual image is formed when diverging rays appear to converge at a point behind the mirror or lens. If the rays do not actually converge, a virtual image cannot be formed. This can happen with concave mirrors for objects placed within the focal point, or with diverging lenses.
A diverging lens only produces a virtual image because the light rays never:?
converge. Instead of meeting at a point to form a real image, the diverging lens causes the light rays to spread out, resulting in a virtual image that appears to be located on the same side as the object.
What are virtual and real images and what is the difference between them?
Here we have to note down an interesting point. If we have a source of light, then the rays starting right from the source would be diverging definitely. Hence if the rays coming from a source is of diverging type then the source is a real one. If otherwise the rays assumed coming from a source is converging type then we can declare that the source would be a virtual one. Same manner to form an image on a screen the rays have to converge. So converging rays would give definitely a real image. If the rays which are destined to give an image are of diverging type then the image must be termed as virtual. To get the position of the virtual image we have to extend back the rays so as they meet at a point and we say that the rays appear to diverge from that point hence named as virtual image. Thus we generalize this way. In case of source if rays are of diverging then source is real, if converging then source is virtual. In case of image formation, if rays are converging then real image and if diverging then virtual image. This is the cute point to be realized and to be taught to the students of this generation.
Which lens does not form a real image?
concave lens does not form a rel image and convex MIRROR does not form a real image
Why can you not form a real image on the screen using a single diverging lens?
A single diverging lens always produces a virtual image. This is because the light rays that pass through the lens appear to diverge as they are traced back on the same side as the object, making it impossible for them to converge to form a real image on a screen.
Can not form virtual image?
A virtual image is formed when diverging rays appear to converge at a point behind the mirror or lens. If the rays do not actually converge, a virtual image cannot be formed. This can happen with concave mirrors for objects placed within the focal point, or with diverging lenses.
Why real image don't form in plane mirror?
When diverging rays from a point source fall on the plane mirror, after reflection would once again diverge and never get a chance of converging. So any diverging rays cannot form a real image and they are considered to be coming from one point and that point is taken to be the virtual image.
A diverging lens only produces a virtual image because the light rays never:?
converge. Instead of meeting at a point to form a real image, the diverging lens causes the light rays to spread out, resulting in a virtual image that appears to be located on the same side as the object.
What does diverging boundaries form?
is a boundary
An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?
An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?Diverging lens do not form real images.When parallel rays of light passes thru a diverging lens, the rays diverge (spread apart) on the other side of the lens. It forms a virtual image. The object will look smaller.The image is on the same side of the lens as the object, so f is negative.Do = 51mm Ho = 13mmDi = ______ Hi = 3.5mmDi = -13.7mm1/Di + 1/Do = 1/f1/-13.5 + 1/51 = 1/ff = -18.36 mm
Why do you get a virtual image?
In case of a concave lens the only possibility is that when parallel rays make an entry then they have to diverge. NO diverging rays can form a real image on a screen as they could not meet at a point. If the already diverging rays make an entry then they get diverged further and so no chance of getting real image. Hence the diverging rays appear to originate from a point on the same side of the object and so a virtual image. In case of a convex lens if the object is placed in between the optic centre and the focal plane then the refracting rays have to diverge and so virtual image. This is what a palmist does as he uses to see the lines on the palm to foretell the future.
What are virtual and real images and what is the difference between them?
Here we have to note down an interesting point. If we have a source of light, then the rays starting right from the source would be diverging definitely. Hence if the rays coming from a source is of diverging type then the source is a real one. If otherwise the rays assumed coming from a source is converging type then we can declare that the source would be a virtual one. Same manner to form an image on a screen the rays have to converge. So converging rays would give definitely a real image. If the rays which are destined to give an image are of diverging type then the image must be termed as virtual. To get the position of the virtual image we have to extend back the rays so as they meet at a point and we say that the rays appear to diverge from that point hence named as virtual image. Thus we generalize this way. In case of source if rays are of diverging then source is real, if converging then source is virtual. In case of image formation, if rays are converging then real image and if diverging then virtual image. This is the cute point to be realized and to be taught to the students of this generation.
No image forms when an object is placed at the focal point of a concave what?
When an object is placed at the focal point of a concave mirror, no real image is formed. This is because the reflected rays are diverging and do not converge to form a real image. Instead, a virtual image is formed behind the mirror, which cannot be projected onto a screen.
A convex lens can produce a real or a virtual image.?
A convex lens can produce a real image when the object is beyond the focal point and the light rays converge at a point to form an image. It can also produce a virtual image when the object is placed within the focal point and the diverging light rays appear to come from a point behind the lens.
Can a concave lens form a real image?
Never. Since the rays coming from a real object will always be diverging. The action of a concave lens is diverging action. Hence the already diverged rays will be dirverged further. Hence no chance of convergence. Only converging rays would form a real image. Hence the answer, NEVER.
