No, that's not true. It's the other way round - light from the object hits our eyes.
We see the light that enters our eye.
The color of a non-luminous object is determined by the way it reflects light. Objects appear to have color based on the wavelengths of light that are reflected off their surfaces and into our eyes. The color we perceive depends on the specific wavelengths of light that are reflected and absorbed by the object.
Blue objects absorb most of the red light that hits them, reflecting very little red light back to our eyes. This causes the object to appear black in red light because red light is the only color that can reveal the object's true color.
The object would appear black. If it were literally absorbing all light and reflecting no light, then you'd be able to see it by contrast with the background... unless the background were also true black, in which case you couldn't see it at all.
An object that looks red is absorbing all colors of light except for red, which is being reflected off the object and detected by our eyes. This object appears red because our eyes perceive the red light that is bouncing off of it. The color red has a longer wavelength compared to other colors, making it appear red to our eyes.
True. Objects can appear to be different colors depending on the color of light that is illuminating them. This is due to the way the object reflects or absorbs different wavelengths of light.
The color of a non-luminous object is determined by the way it reflects light. Objects appear to have color based on the wavelengths of light that are reflected off their surfaces and into our eyes. The color we perceive depends on the specific wavelengths of light that are reflected and absorbed by the object.
Blue objects absorb most of the red light that hits them, reflecting very little red light back to our eyes. This causes the object to appear black in red light because red light is the only color that can reveal the object's true color.
The object would appear black. If it were literally absorbing all light and reflecting no light, then you'd be able to see it by contrast with the background... unless the background were also true black, in which case you couldn't see it at all.
An object that looks red is absorbing all colors of light except for red, which is being reflected off the object and detected by our eyes. This object appears red because our eyes perceive the red light that is bouncing off of it. The color red has a longer wavelength compared to other colors, making it appear red to our eyes.
True.
True. Objects can appear to be different colors depending on the color of light that is illuminating them. This is due to the way the object reflects or absorbs different wavelengths of light.
Yes, that is correct. Please note that the object itself doesnt create the light - it mearly relfects the ambient light (which, for example, comes from light blubs or the sun). It is this reflected light that the eye picks up and - with help from the brain - interprets into an image which we "see".
Newton's law doesn't say anything about heavy and light. The 'law' talks in terms ofthe mass of the object, and it's true even in space, where the objects have no weightat all.
In dim light, there is less light available for our eyes to detect colors accurately. Our eyes rely on cones, specialized cells in the retina, to distinguish colors, and these cones are less effective in low light conditions. This makes it difficult to perceive true colors in dim lighting.
Our eyes have both black-and-white receptors, and color receptors. The black-and-white receptors work at low light levels; the color recepters require a higher light intensity.
Yes, when light is absorbed by an object, the light energy is generally transformed into other forms of energy, such as heat or chemical energy. This stored energy can then be used by the object for various purposes.
true