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Yes, power is directly proportional to current. Power is equal to amps times volts, and as current goes up (with voltage remaining constant), power will go up. Double current, and you'll double power. Cut current in half, and you'll cut power in half. (Voltage stays the same in all this).
Wiki User
∙ 14y ago
Wiki User
∙ 11y agoYes, as long as the load impedance (resistance) is constant.
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Is the current directly proportional to the change in temp?
hi! no the current squared is directly proportional to the change in temp, Joules Law
Is there a direct or inverse proportion between voltage and resistance?
voltage is directly proportional to resistance, and the current is inversely proportional to resistance. According to Ohm's Law, current is directly proportional to voltage.
How are current and voltage related are they directly proprtional or inversely proportional?
Current and Voltage are directly proportional. V=voltage, I=current, R=resistance V=I*R
Terms of direct square proportionality in physics?
If x and y have a direct square relationship it means that the term x is proportional to a constant multiplied by y squared x=ky^2 or to simplify x is proportional to y squared.
Ohm's law shows that current is directly proportional to the applied voltage and is inversely proportional to resistance?
Yes! Good work.
How Attenuation measured?
RMS Output divided by input, usually expressed in deciBells. Depends on whether it is power or voltage being attenuated. Voltage, it's 20log(Vout/Vin) Power, it's 10log(Pout/Pin) The difference is because power is proportional to voltage squared.
What are the relationships between current power and resistance?
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
How do you show resistance is proportional to L squared?
Okay. Resistance by ohms law is given by R = V/I But Power P = V * I Dividing R/P = 1/ I 2 Or R = P / I squared For a constant power, resistance is inversely proportional to I squared and not simply proportional to.
If voltage and current are proportional why do they increase voltage in powerlines in order to decrease current?
Low current will equal low power losses due to the resistance of the cable. I squared R. (I is transmission current and R is resistance/Metre of cable) by increasing the voltage for the same amount of power the current decreases. Power transmission will take that advantage to transfer less current for the same amount of power.
What do you mean by power is directly proprtional to voltgae?
That statement is not correct. Power is proportional to the square of the voltage. "Power is directly proportional to voltage" claims that there is a relationship of the type: P=kV, where power is voltage, multiplied by some constant. That means for example that if voltage doubles, power doubles as well. The correct relation is: power is proportional to the square of the voltage. That means that if voltage doubles, power increases by a factor of 4. In general, such as square proportion might be written as: P = kV2 for some constant k. The relevant law in this case is: P = (1/R)V2 where "R" is the resistance.
Why do you think as the voltage across a lamp changes the power consumption?
Because the power of a resistive component is directly proportional to the square of the voltage across that component.
Is the current directly proportional to the change in temp?
hi! no the current squared is directly proportional to the change in temp, Joules Law
What are electric power?
Power can be found by the following equations depending upon what information you have available. Power = Voltage x Current ; P=VI Power = Current Squared x Resistance ; P=I2R Power = Voltage Squared / Resistance ; P=V2/R
What is the two formulas for getting power?
In general:Power = energy transfer divided by timeIn electric circuits:Power = current x voltage x power factorPower = current squared x resitancePower = voltage squared / resistance
WHAT ARE Electric power CALCULATIONS?
Power can be found by the following equations depending upon what information you have available. Power = Voltage x Current ; P=VI Power = Current Squared x Resistance ; P=I2R Power = Voltage Squared / Resistance ; P=V2/R
Why you take cutoff freqency at 3dB?
3 dB implies 1/2 the power and since the power is proportional to the square of voltage, the voltage will be 0,707 of the passband voltage. sqrt(0.5) = 0.707
What are the advantages of transmitting electric power at high voltage levels?
For a given amount of power, the higher the voltage the lower the current. This is necessary to minimise the voltage drop along the transmission line, and to reduce energy losses which are proportional to current squared. The advantage of transmiting electrical power at high(er) voltages is that you can use smaller conductors, since the current flow would be less for the same amount of watts. Watts = Volts times Amperes
