More than doubled.
The stopping voltage is the photon energy minus the work function:
hv - W
Doubling the photon energy creates a new stopping voltage of:
2 hv - W > 2 (hv - W)
Intensity of a wave is proportional to the frequency squared and amplitude squared based on this formula; I=1/2pw^2A^2V where p is the density of the medium, w is the angular frequency and A is the amplitude and V is the wave velocity. So, everything else remaining constant, decreasing the amplitude will decrease a waves intensity. Example decreasing the the amplitude by a factor of 4 will decrease the wave intensity by a factor of 8.
the frequency!:-)
E = h f (relation of energy with frequency) E = h c / λ (relation of energy with wavelength) h = Planck's constant ≈ 6.026 × 10⁻³⁴ J.s c = speed of light = 299,792,458 m/s in vacuum ≈ 3.0 × 10⁸ m/s
Frequency is the amount of bumps there are in the wave. The higher the frequency the lower the wave length and vise versa. some equations are E=hv C=vw h=Plancks Constant(6.626x10 to the -34) C=3.0x10 to the power of 8
The frequency of the applied voltage is constant.
The increased frequency increases the kinetic energy of the single electron ejected. Remember that the incident light releases a single electron when the threashod frequency is reached
In transformer there is no rotating part.so frequency constant.
It doesn't, from the equation E = h*f (E is energy, h is Planck's constant, f is frequency) you can clearly see that energy is a function of frequency, not amplitude (intensity). Therefore, it doesn't even matter what the relationship between stopping potential and energy is, because it will only depend on frequency, which is sufficient knowledge to answer this question.
Intensity of a wave is proportional to the frequency squared and amplitude squared based on this formula; I=1/2pw^2A^2V where p is the density of the medium, w is the angular frequency and A is the amplitude and V is the wave velocity. So, everything else remaining constant, decreasing the amplitude will decrease a waves intensity. Example decreasing the the amplitude by a factor of 4 will decrease the wave intensity by a factor of 8.
the frequency!:-)
The frequency depends on what the frequency is of. A pendulum or other simple harmonic motion has a constant frequency, a Poisson event has a variable frequency, although the long term average is a constant.
E = h f (relation of energy with frequency) E = h c / λ (relation of energy with wavelength) h = Planck's constant ≈ 6.026 × 10⁻³⁴ J.s c = speed of light = 299,792,458 m/s in vacuum ≈ 3.0 × 10⁸ m/s
the wavelength changes when the frequency changes if the wavelengths are smaller and thinner then the frequency is high, when the frequency is slow then the wavelengths is larger and wider. if the frequency is constant then the wavelength is a normal size
Frequency is the amount of bumps there are in the wave. The higher the frequency the lower the wave length and vise versa. some equations are E=hv C=vw h=Plancks Constant(6.626x10 to the -34) C=3.0x10 to the power of 8
frequency = speed of wave / wavelength so if speed is constant then frequency varies inversely with wavelength
Coherence relates to the physics of waves. Specifically, it refers to a property that allows constant interference. Because interference varies the intensity of light, coherent light has a relatively stable intensity.
The photon energy is directly proportional to its frequency: Energy = Planck's constant * frequency.