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A girl pulling her cart .who is the one doing work?
The girl is the one doing the work by pulling the cart.
What expression can be found to represent the total work done by the agent pulling the loop?
The total work done by the agent pulling the loop can be represented by the expression "work equals force times distance."
If A 70 kg cart is pushed for 50 m with a constant velocity upon a 45º frictionless incline Find the work done on the cart?
The work done on the cart is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, since the incline is frictionless, the only force doing work is the force of gravity. The work done would be the force of gravity acting on the cart multiplied by the distance along the incline.
A student does 300 joules of work pushing a cart 3.0 meters due east and then does 400 joules of work pushing the cart 4.0 meters due north the total amount of work done by the student is?
Oh, dude, let's break it down. So, the work done is the force applied times the distance moved in the direction of the force, right? Like, in this case, the work done pushing east is 300 J and pushing north is 400 J. Since work is a scalar quantity, you just add them up - 300 J + 400 J = 700 J. That's the total amount of work done by the student. Easy peasy, lemon squeezy!
Is it true that rolling a cart up a ramp is an example of doing negative work?
No, rolling a cart up a ramp is an example of doing positive work, as energy is being transferred to the cart to lift it against gravity. Negative work would be done if the cart were rolling down the ramp, as energy would be lost against gravity.
A girl pulling her cart .who is the one doing work?
The girl is the one doing the work by pulling the cart.
What is the work being done the girl pulling her cart?
The force exerted by the girl in pulling the toy car is in the same direction as the distance covered when the force is applied.
What expression can be found to represent the total work done by the agent pulling the loop?
The total work done by the agent pulling the loop can be represented by the expression "work equals force times distance."
Why would a cart start moving faster if you gave it hard push than if you gave it a soft push?
When u push the cart,u apply some force on the cart which does the work(the cart moves). The movement of the cart is the work done due to the application of the force you.
If A 70 kg cart is pushed for 50 m with a constant velocity upon a 45º frictionless incline Find the work done on the cart?
The work done on the cart is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, since the incline is frictionless, the only force doing work is the force of gravity. The work done would be the force of gravity acting on the cart multiplied by the distance along the incline.
A student does 300 joules of work pushing a cart 3.0 meters due east and then does 400 joules of work pushing the cart 4.0 meters due north the total amount of work done by the student is?
Oh, dude, let's break it down. So, the work done is the force applied times the distance moved in the direction of the force, right? Like, in this case, the work done pushing east is 300 J and pushing north is 400 J. Since work is a scalar quantity, you just add them up - 300 J + 400 J = 700 J. That's the total amount of work done by the student. Easy peasy, lemon squeezy!
Is it true that rolling a cart up a ramp is an example of doing negative work?
No, rolling a cart up a ramp is an example of doing positive work, as energy is being transferred to the cart to lift it against gravity. Negative work would be done if the cart were rolling down the ramp, as energy would be lost against gravity.
How much work is done pushing a shopping cart 100 meters with a force of 88N?
The work done pushing the shopping cart would be 8800 Joules, calculated as force (88N) times distance (100m). Work is the product of force applied in the direction of motion and the distance over which it is applied.
How much work is done by a person who pushes a cart with a force of 40 newtons if the car moves 10 meters in the direction of the force?
The work done by the person is calculated as the force applied multiplied by the distance the cart moves in the direction of the force. In this case, the work done would be 40 newtons x 10 meters = 400 joules.
What amount of work is done on a cart that is pushed 4 meter across a floor by a horizontal 50 Newton net force?
The work done on the cart would be 200 Joules. This is calculated using the formula Work = Force x Distance, where Work = 50 N x 4 m = 200 J.
A student does 300 joules of work pushing a cart 3 meters due east then does 400 joules of work pushing the cart 4 meters due north the total amount of work done by the student is what?
700 joules
Rolling a cart up a ramp is an example of doing negative work true or false?
False. Rolling a cart up a ramp is an example of doing positive work. Work is done when a force is applied to move an object in the direction of the force, such as lifting a weight or pushing a cart uphill.
