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Measure the amount of water that was displaced with the clay lump and floating clay shape how do these amounts compare?
Wiki User
∙ 12y ago
Because if you were too get clay lump and the floating clay shape because it's more dense
Wiki User
∙ 12y ago
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How does the buoyant force on a fully submerged object compare with the water displaced?
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
How does the weight of water displaced compare to buoyant force?
They are equal.
How does the volume of a fully submerged object compare with the volume of water displaced?
They're equal.
How does the ml of a completely submerged object compare with the ml of water displaced?
Those volumes are equal.
How does the buoyant force on a fully submerged object compare with the weight of the water displaced?
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
How does the mass of a floating wood compare to the mass of water displaced?
equal
How does the buoyant force on a fully submerged object compare with the water displaced?
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
What amounts do you compare when measureing concentration?
To measure concentration, you compare the amount of the solute to the total amount of the solution.
What is a math scale?
A math scale is a set of numbers or amounts used to measure or compare the level of something .
How does the weight of water displaced compare to buoyant force?
They are equal.
You can use what to compare and measure the volume of two solid boxes?
Use water and a cylinder marked with measurements. Use the amount of water displaced to compare the volume/ +++ You can indeed, but if the blocks are small enough to handle and of regular polyhedral form, it may be simpler just to use a rule to measure them directly.
How would you verify the Archimedes principle for objects that are less dense than the liquid?
Two ways to do this: 1) Floating the less dense object on the more dense liquid. To verify the Archimedes principle you need to show that the mass of the liquid displaced by the less dense object is equal to the mass of the less dense object. To do this you need to have a way to determine the mass of the displaced liquid. If the liquid is in a container filled to the brim, then when you place the less dense object in it, the displaced liquid will spill out over the edges of the container. If you can collect and weight that liquid, then you can compare its weight to the weight of the less dense object - they should match. Alternatively, you can find a way to measure the volume of the displaced liquid and calculate the mass from the volume and density of the displaced liquid. 2) Immerse the object completely in the liquid and measure the force required to keep it submerged. This one is more complicated and difficult to execute and measure. The force required to keep the less dense object submerged should be the difference between the weight of the object (when it is not in the liquid) and the weight of the displaced liquid.
How does the buoyant force on a submerged object compare with the weight of water displaced?
They are equal.
How does the volume of completely submerged object compare with the volume of water displaced?
They are equal.
How does the volume of a fully submerged object compare with the volume of water displaced?
They're equal.
0.142 Hector equal to how many yards?
Hectar is a measure of area, not of length. You can't compare that.Hectar is a measure of area, not of length. You can't compare that.Hectar is a measure of area, not of length. You can't compare that.Hectar is a measure of area, not of length. You can't compare that.
How does the ml of a completely submerged object compare with the ml of water displaced?
Those volumes are equal.
